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It's the sum of the following probabilities:

(4/52) * (36/51) * (35/50) * (34/49) * (33/48) = 1.81%

(36/52) * (4/51) * (34/50) * (33/49) * (32/48) = 1.66%

(36/52) * (35/51) * (4/50) * (33/49) * (32/48) = 1.71%

(36/52) * (35/51) * (34/50) * (4/49) * (32/48) = 1.76%

(36/52) * (35/51) * (34/50) * (33/49) * (4/48) = 1.81%

total = 8.75%

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Q: What is the probability of being dealt exactly one Ace and no face cards in a five card poker hand?
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