Counting Aces as a face card, the answer is 0.0241 If Aces are not considered face cards, then the answer is 0.0181
The odds of any card pulled from an ordinary deck of 52 cards being an Ace is 4 in 52 (4 aces in a deck of 52). This can be reduced to a 1 in 13 chance of any random card pulled from the deck being an Ace (or any other specific value, for that matter). That 13th last card dealt in a hand is no different than picking a random card out of the pack, regardless of what cards you deal before (face down or blindfolded or even face up, it doesn't matter). A more interesting question would be "what would the probability be of ANY of those 13 cards being an Ace?" Any takers?
Counting Aces as face cards, the probability is 16/52 or 4/13.
There are 12 face cards in a standard deck of 52 cards. The odds of the first card being a face card is 12/52. If the first card drawn is a face card then there are 11 face cards remaining in the deck of 51 cards. The odds of a second draw of a face card is then 11/51. If both the first two cards drawn were face cards then the deck has 10 face cards in 50 total card. The odds of the third card also being a face card is 10/50. The total probability is (12/52)*(11/51)*(10/50) = 0.009954751 or just under one percent of the time.
There are 12 face cards in a standard deck of 52 cards; the jacks, queens, and kings of spades, diamonds, clubs, and hearts. The probability, then, of drawing a face card is 12 in 52, or 3 in 13, or about 0.2308.
The probability that the first four cards are face cards is (16/52)*(15/51)*(14/50)*(13/49) = 43680/6497400 = approx 0.0067
Counting Aces as a face card, the answer is 0.0241 If Aces are not considered face cards, then the answer is 0.0181
The odds of any card pulled from an ordinary deck of 52 cards being an Ace is 4 in 52 (4 aces in a deck of 52). This can be reduced to a 1 in 13 chance of any random card pulled from the deck being an Ace (or any other specific value, for that matter). That 13th last card dealt in a hand is no different than picking a random card out of the pack, regardless of what cards you deal before (face down or blindfolded or even face up, it doesn't matter). A more interesting question would be "what would the probability be of ANY of those 13 cards being an Ace?" Any takers?
The probability of a random card from a pack of 52 cards being a spade or a face card is 11 in 26. There are 13 spades and 12 face cards, with 3 of the face cards being spades, so there are 22 possible cards (13 + 12 - 3) that are spades or face cards. The probability is 22 in 52, or 11 in 26.
There are 3 face cards in a suit of 13 cards, so the probability is = 3/13.
Counting Aces as face cards, the probability is 16/52 or 4/13.
There is a .53846 probability (53.846%) if aces are counted as face cards. If they are not counted the probability drops to .48077 (48.077%)
There are 52 cards in a deck and 12 face cards (J,Q,and K) so probability is 12/52 = 3/13
The probability of getting a face card or a red card in a standard deck of 52 cards is (26 + 12 - 3) in 52 or 35 in 52 or about 0.6731.26 red cards, 12 face cards, and 3 red cards that are also face cards.
The probability of drawing the first face card is 12 in 52. The probability of drawing the second is 11 in 51. The probability of drawing the third is 10 in 50. Thus, the probability of drawing three face cards is (12 in 52) times (11 in 51) times (10 in 50) or (1320 in 132600) or about 0.009955.
There are 36 number cards, 12 face cards, and 4 aces. So the probability of your first card from a full pack being a number card is 36:16, or 9:4.
There are 12 face cards in a standard deck of 52 cards. The odds of the first card being a face card is 12/52. If the first card drawn is a face card then there are 11 face cards remaining in the deck of 51 cards. The odds of a second draw of a face card is then 11/51. If both the first two cards drawn were face cards then the deck has 10 face cards in 50 total card. The odds of the third card also being a face card is 10/50. The total probability is (12/52)*(11/51)*(10/50) = 0.009954751 or just under one percent of the time.