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What is the probability of drawing the ace of hearts first than the ace of diamonds?
Wiki User
∙ 12y ago
The probability of drawing the Ace of Hearts from a standard deck of 52 cards is 1 in 52. The probability of then drawing the Ace of Diamonds is then 1 in 51. Multiply these two probabilities together, and you get 1 in 2652, or about 0.0003771.
The probability of drawing the ace of hearts from a deck before drawing the ace of diamonds, ignoring any other cards, is 1/2.
Note: Both of these answers are correct. It depends on your point of view. They've been left so that you, dear reader, can think about it.
Wiki User
∙ 12y ago
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What is the probability of drawing two hearts from a deck of fifty-two playing cards?
The probability of getting two hearts in a row: P(Getting a hearts on the first draw)*P(Getting another hearts given the first one was a hearts) The first probability is simple: there are 13 hearts in a deck of 52 cards. The probability is 13/52=1/4. The second probability is trickier: there are now 12 hearts left in a deck of 51 cards! The probability of getting another hearts is therefore 12/51=4/17. Now compute (1/4)*(4/17) and get 1/17, which is the probability of drawing two hearts from a deck of fifty-two playing cards.
What is the probability of get ace of spades on first draw and get queen of hearts on second draw?
The probability of drawing the Ace of Spades on the first draw is 1 in 52. The probability of drawing the Queen of Hearts on the second draw is 1 in 51. The probability of both of those event occurring is 1 in 2652. (1 in 52) times (1 in 51)
What is the probability of drawing 3 cards that are all face cards?
The probability of drawing the first face card is 12 in 52. The probability of drawing the second is 11 in 51. The probability of drawing the third is 10 in 50. Thus, the probability of drawing three face cards is (12 in 52) times (11 in 51) times (10 in 50) or (1320 in 132600) or about 0.009955.
What is the probability of drawing 2 cards that are a 2 from a deck of 52?
The probability of drawing 2 cards that are two's from a standard deck of 52 playing cards is 1 in 221. The probability of drawing the first two is 4 in 52 or 1 in 13. The probability of drawing the second two is 3 in 51. Multiply those two probabilities together and you get 3 in 663, or 1 in 221.
What is the probability of drawing a red card and a 7 in a deck of cards?
The probability of doing so, if the first card is not replaced, is 0.0385, approx.
What is the probability of drawing 2 hearts in a deck of cards?
The probability of drawing the two of hearts is 1/52. The probability of drawing two cards that are hearts depends on whether or not the first card is replaced. If it is replaced, then the probability is (1/4)*(1/4) = 1/16 = 0.0625 while if it is not, the probability is (1/4)*(12/51) = 3/51 = 0.0588 (approx).
What is the probability of drawing two hearts from a deck of fifty-two playing cards?
The probability of getting two hearts in a row: P(Getting a hearts on the first draw)*P(Getting another hearts given the first one was a hearts) The first probability is simple: there are 13 hearts in a deck of 52 cards. The probability is 13/52=1/4. The second probability is trickier: there are now 12 hearts left in a deck of 51 cards! The probability of getting another hearts is therefore 12/51=4/17. Now compute (1/4)*(4/17) and get 1/17, which is the probability of drawing two hearts from a deck of fifty-two playing cards.
What is the probability of get ace of spades on first draw and get queen of hearts on second draw?
The probability of drawing the Ace of Spades on the first draw is 1 in 52. The probability of drawing the Queen of Hearts on the second draw is 1 in 51. The probability of both of those event occurring is 1 in 2652. (1 in 52) times (1 in 51)
What is the probability of drawing 2 hearts and then a spade in that order from a deck of 52 cards?
In order to determine the probability of drawing 2 hearts and then a spade, in that order, from a deck of 52 cards, start by considering the first card. The probability of drawing a heart is 1 in 4. Since you have now reduced the number of hearts and the number of cards in the deck by one, the probability of drawing another heart is 4 in 17. Since you have further reduced the number of cards by one, the probability of drawing a spade is 13 in 50. Multiply these probabilities together, (1/4) (4/17) (13/50), and you get about 0.0153, or about 153 in 10000.
Out of a standard 52 card deck what is the probability of drawing a heart given that a red card was drawn first?
This is a conditional probability, given the card is red, what is the chance it is a heart. Since there are 2 red hearts, the probability if 1/2
If you select two cards from a deck of 52 cards what is the probability that the first card is an 6 of diamaond and the second card is an 3 of hearts?
First off, how do I calculate the probability that any one event occurs. The answer is equal to: Number of Possible Chances of Success / Total Number of Chances In this case, the number of possible chances of success is one (there is only one 6 of Diamonds in any deck of cards). The total number of chances equal 52 (there are 52 cards to choose from). Therefore the probability of picking a 6 of Diamonds on the first card is 1/52 or .019. In order to calculate the probability that the first card is a 6 of Diamonds AND the second card is a 3 of Hearts, you multiply the two probabilities. Prob. of 1st Card 6D AND 2nd Card 3H = Prob. 1st Card 6D * Prob. 2nd Card 3H We already know the probability of getting a 6 of Diamonds on the first card is 1/52 or .019. To calculate the probability of getting a 3 of Hearts on the second card, it is important to remember that random occurances do not affect the probability of other random occurrances. What I mean is, if I were to draw a 6 of Diamonds from a deck of cards and then replace it, the probability that I would pick a 6 of Diamonds again is the same as it was the first time. Even if I flip a coin 5 times in a row and they all landed on heads, the probability that I would flip another heads is still 50/50. So basically we can ignore what happened on the first draw, and jsut calculate the probability of getting a 3 of Hearts. Again we use our probability formula: Number of Possible Chances of Success / Total Number of Chances In this case, the number of possible chances of success is one (there is only one 3 of Hearts in any deck of cards). The total number of chances equal 52 (THIS ASSUMES THAT WE PUT THE 6 OF DIAMONDS BACK INTO THE DECK AFTER THE FIRST DRAW IF NOT THE NUMBER OF CHANCES IS 51). Therefore the probability of picking a 3 of Hearts on the second card is 1/52 or .019. Multiply the two probabilities together to get the probability of both occurring: 1/52 * 1/52 = 1/2704 = .00037 (or a .037 percent of a chance)
What is the probability of drawing three aces in a row without replacement?
The probability of drawing aces on the first three draws is approx 0.0001810
What is the probability of drawing 3 cards that are all face cards?
The probability of drawing the first face card is 12 in 52. The probability of drawing the second is 11 in 51. The probability of drawing the third is 10 in 50. Thus, the probability of drawing three face cards is (12 in 52) times (11 in 51) times (10 in 50) or (1320 in 132600) or about 0.009955.
What is the Probability of drawing two spades out of 52 cards?
The probability of drawing a spade in a standard 52 card deck is 13 in 52, or 1 in 4. The probability of drawing a second spade, assuming the first spade was not replaced back into the deck, is 12 in 51. The probability, then, of drawing two spades is the product of those two probabilities, or 12 in 204, or 1 in 17.
What is the probability of drawing 2 cards that are a 2 from a deck of 52?
The probability of drawing 2 cards that are two's from a standard deck of 52 playing cards is 1 in 221. The probability of drawing the first two is 4 in 52 or 1 in 13. The probability of drawing the second two is 3 in 51. Multiply those two probabilities together and you get 3 in 663, or 1 in 221.
What is the probability drawing an ace followed by a king?
If only two cards are drawn from a standard deck of cards, with the first card replaced before drawing the second, the answer is 0.005917 (approx). If the first card is not replaced, the probability increases to 0.006033.
A pack of cards is shuffled and one is drawn out at random 80 times what is the probability of drawing a spade?
Given the way you have worded the question I take it to mean, what is the probability of drawing at least one spade?We can do this most easily by asking first, what is the probability of drawing no spades on each of the 80 times. This is 39/52. The probability of doing this 80 times is (39/52)80.Then the probability of not doing this is 1 - (39/52)80, which is quite close to one. The probability of drawing at least one spade is almost one.
