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What is the probability of get ace of spades on first draw and get queen of hearts on second draw?
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∙ 14y ago
The probability of drawing the Ace of Spades on the first draw is 1 in 52. The probability of drawing the Queen of Hearts on the second draw is 1 in 51. The probability of both of those event occurring is 1 in 2652. (1 in 52) times (1 in 51)
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∙ 14y ago
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What is the probability of drawing an ace of spades on the first draw and a four of spades on the second draw using sampling without replacement.... how do you go about doing this problem?
There are 52 cards in the deck.The probability of drawing the ace of spades on the first draw is 1/52 .Since you don't put the first card back, there are then 51 cards in the deck.The probability of drawing the 4 of spades on the second draw is 1/51 .The probability of both occuring is (1/52) x (1/51) = 1/2,652 = 0.037707 % (rounded)
What is the probability of drawing two hearts from a deck of fifty-two playing cards?
The probability of getting two hearts in a row: P(Getting a hearts on the first draw)*P(Getting another hearts given the first one was a hearts) The first probability is simple: there are 13 hearts in a deck of 52 cards. The probability is 13/52=1/4. The second probability is trickier: there are now 12 hearts left in a deck of 51 cards! The probability of getting another hearts is therefore 12/51=4/17. Now compute (1/4)*(4/17) and get 1/17, which is the probability of drawing two hearts from a deck of fifty-two playing cards.
How do you find the probability of picking a king of spades and the ace of hearts out of 52 cards?
2 in 2652, or about 0.0007541. (2 in 52 times 1 in 51)Detailed Explanation:Initially, you have 52 cards. The King of Spades and the Ace of Hearts are two of them, so you have a 2 in 52 chance of picking the King of Spades or the Ace of Hearts on your first draw. On your second draw, you have to pick the other card, but now there are only 51, so the chance of picking the other one is 1 in 51.Since these are independent, though sequentially related events, to compute the probability that both events occur, you simply multiply the two probabilities together. 2 in 52 times 1 in 51 is 2 in 2652, or about 0.0007541.
If you Have a deck of 52 cards What is the probability that first 4 are spades?
The probability of drawing 4 spades from a deck of 52 cards is 11 in 4165. The probability of the first spade is 13 in 52, or 1 in 4. The second spade is 12 in 51, or 4 in 17. The third spade is 11 in 50. The fourth spade is 10 in 49. Multiply these four probabilities together and you get 440 in 166600, or 11 in 4165.
What is the probability of rolling a 6 the first time and a 1 the second time?
What is the probability of rolling a 6 the first time and a 1 the second time
What is the probability of drawing an ace of spades on the first draw and a four of spades on the second draw using sampling without replacement.... how do you go about doing this problem?
There are 52 cards in the deck.The probability of drawing the ace of spades on the first draw is 1/52 .Since you don't put the first card back, there are then 51 cards in the deck.The probability of drawing the 4 of spades on the second draw is 1/51 .The probability of both occuring is (1/52) x (1/51) = 1/2,652 = 0.037707 % (rounded)
What is the probability of drawing two hearts from a deck of fifty-two playing cards?
The probability of getting two hearts in a row: P(Getting a hearts on the first draw)*P(Getting another hearts given the first one was a hearts) The first probability is simple: there are 13 hearts in a deck of 52 cards. The probability is 13/52=1/4. The second probability is trickier: there are now 12 hearts left in a deck of 51 cards! The probability of getting another hearts is therefore 12/51=4/17. Now compute (1/4)*(4/17) and get 1/17, which is the probability of drawing two hearts from a deck of fifty-two playing cards.
What is the Probability of drawing two spades out of 52 cards?
The probability of drawing a spade in a standard 52 card deck is 13 in 52, or 1 in 4. The probability of drawing a second spade, assuming the first spade was not replaced back into the deck, is 12 in 51. The probability, then, of drawing two spades is the product of those two probabilities, or 12 in 204, or 1 in 17.
How do you find the probability of picking a king of spades and the ace of hearts out of 52 cards?
2 in 2652, or about 0.0007541. (2 in 52 times 1 in 51)Detailed Explanation:Initially, you have 52 cards. The King of Spades and the Ace of Hearts are two of them, so you have a 2 in 52 chance of picking the King of Spades or the Ace of Hearts on your first draw. On your second draw, you have to pick the other card, but now there are only 51, so the chance of picking the other one is 1 in 51.Since these are independent, though sequentially related events, to compute the probability that both events occur, you simply multiply the two probabilities together. 2 in 52 times 1 in 51 is 2 in 2652, or about 0.0007541.
If you Have a deck of 52 cards What is the probability that first 4 are spades?
The probability of drawing 4 spades from a deck of 52 cards is 11 in 4165. The probability of the first spade is 13 in 52, or 1 in 4. The second spade is 12 in 51, or 4 in 17. The third spade is 11 in 50. The fourth spade is 10 in 49. Multiply these four probabilities together and you get 440 in 166600, or 11 in 4165.
The second card is hearts given that the first is red?
Since the first card is red, that eliminates all spades and clubs, leaving the hearts and diamonds. If the first card is replaced then the probability is 1/2. If the first card is not replaced then the probability is 12/25 if the first card is a heart, or 13/25 if the first card is a diamond
What is the probability that one of two consecutive cards is a spade?
From a standard deck of playing cards, there are 52 cards. There are 13 cards for each Spades, Hearts, Clubs and Diamonds. For the first card, the probability of getting a Spade is 13/52. If you're going to replace the first card into the deck, then the probability of second card being a Spade is also 13/52 Therefore, 13/52 x 13/52 = 1/16 (one in every sixteen tries) If you're not going to replace the first card into the deck, the remaining deck will be left with a total of 51 cards and 12 Spades. Therefore the probability of second card being a Spade is 12/51 Lastly, 13/52 x 12/51 = 1/17 (one in every seventeen tries)
Does spades beat hearts poker?
Its the numbers that matter. (in for of a kind) The suit strength is based on the first letter of the suit.
What is the probability of drawing an ace of spades and a heart from a deck of cards in two successive draws without placing the first card back in the deck of 52?
There's only one Ace of spades in a 52 card deck so it's 1/52 times the probability of drawing a heart (there are 13 hearts in the same deck, but now there are 51 cards because we already drew one out). That makes it 1/52 * 13/51 = 13/2652 = 1/204 This is if you want the Ace first, then the heart, if order doesn't matter, you add this to the probability of drawing the heart first, then the Ace of Spades which is (13/52*1/51) =1/204 notice is the same as the first one. So if order doesn't matter, the probability is 1/204 + 1/204 = 2/204 = 1/102
What is the probability of drawing 2 hearts in a deck of cards?
The probability of drawing the two of hearts is 1/52. The probability of drawing two cards that are hearts depends on whether or not the first card is replaced. If it is replaced, then the probability is (1/4)*(1/4) = 1/16 = 0.0625 while if it is not, the probability is (1/4)*(12/51) = 3/51 = 0.0588 (approx).
What is the probability of rolling a 6 the first time and a 1 the second time?
What is the probability of rolling a 6 the first time and a 1 the second time
What is the probability from drawing 4 spades from a deck of cards?
In an ordinary deck of cards, there are 52 cards out of which 13 are spades. This means that the chances of drawing the first spade is 13 out of 52. The probability of the second spade is 12 out of 51 because one spade and, incidentally, one card are now missing. The third spade comes out as 11 out of 50 and the last one as 10 out of 49. Total probability of events that don't affect each other is the product of the individual probabilities. Thus, the chances of drawing four spades is (13 / 52) * (12 / 51) * (11 / 50) * (10 / 49), which is about 0.00264 -- in other words, one to 379.
