1/2 if it is a fair coin
1/2
P(tail) is 0.5. You want P(tail) AND P(tail) = 0.5 * 0.5 = 0.25 or 1/4.
1/8 or 12.5%
http://wiki.answers.com/Q/If_you_Flip_four_coins_at_once_what_is_probability_of_2_head_and_3_tail" The probability of flipping four coins and getting 2 heads and 3 tails is ZERO 2 heads and 3 tails requires flipping FIVE coins.
Assume the given event depicts flipping a fair coin and rolling a fair die. The probability of obtaining a tail is ½, and the probability of obtaining a 3 in a die is 1/6. Then, the probability of encountering these events is (½)(1/6) = 1/12.
probability of rolling a 3 = 1/6 probability of flipping a head = 1/2 therefore, overall = 1/12
HHHHHTHTHTHHHTTTHTTTHTTTOf the 8 possibilities, 3 have 2 heads and 1 tails. So the probability is 3/8 (assuming a fair coin)
The probability of flipping Heads on a coin is 1 - a certainty - if the coin is flipped often enough. On a single toss of a fair coin the probability is 1/2.
The probability of rolling a 2 on a die before flipping a heads on a coin is 1 in 12. The probability of rolling a 2 is 1 in 6. The probability of flipping heads is 1 in 2. Since these are sequentially unrelated events, you simply multiply the probabilities together.
50-50
The probability of flipping a Head is the same as that for a Tail and is 1/2 or 50%. The probability of rolling a particular number on a die is 1/6 since there are 6 numbers. Combining these two probabilities (by multiplication) we have, as the combined probability 1/2 x 1/6 = 1/12 = 0.0833333333333333(the 3 recurs) which as a percentage is 8.33333333333%
The probability of flipping a quarter and getting heads is 1 in 2. the probability of rolling a die and getting 6 is 1 in 6.