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Instead of thinking of this as rolling 1 die three times, think of it as rolling 3 dice once. The first die will be something. The 2nd die will have a 1/6 chance of being the same as the first. The 3rd die will have a 1 in 6 chance of being the same as the first. As for the 3rd die matching the 2nd, this gets tricky. There is a 1/6 chance it will be the same as the 2nd, but you must then adjust for the 3rd die being the same as the first and second. Having all three the same would be 1/6 * 1/6 or 1/36. So the probability would be 1/6 + 1/6 - 1/36 or 11/36

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