The answer depends on how careful you are in going through the examination paper!
The probability of drawing a Ace from a standard deck of 52 cards if one Ace is missing is 3 in 51, or about 0.05882. If the missing card is not an Ace, then the probability is 4 in 51, or about 0.07843.
My book is missing page 17. Perhaps you could ask me one of the problems.
The answer depends on what information is available and which bits are missing. Without that information it is not possible to give a particularly useful answer.
My book is missing page 219. Perhaps you could tell me some of the problems.
My book is missing page 220. Perhaps you could tell me some of the problems.
Missing - 2012 Answers 1-8 is rated/received certificates of: Netherlands:12
It is not possible to answer the question because your typo could be tens (with an extra t) on tenths (with a missing h). The two will give different answers.
There are an infinite number of possible answers,depending on what gets multiplied by that number.The answer will be (140)/(the number that's completely missing from the question)
it was Ginny
Conclusions based on missing frequencies are likely to be seriously flawed. However, if the data follow a known distribution, it may be possible to get some indication of the likely values for the missing frequencies. Nevertheless, this would weaken any conclusions.
You want the probability of miss and miss and miss which is .67 * .67 * .67 = 0.301.
The answer will depend on where, in the sequence, the missing number is meant to be. Also, in each case, there are infinitely many possible answers since it is possible to find a polynomial of degree 5 (or higher) that will go through each of the above numbers and ANY other number, missing from ANY position.Using polynomials of order 4, though, there is only one answer for each position. For example,First number missing: 171Un= (-27n4+ 422n3- 2364n2+ 5611n - 4668)/6Last number missing: 218Un= (-27n4+ 314n3- 1260n2+ 2041n - 1026)/6The answer will depend on where, in the sequence, the missing number is meant to be. Also, in each case, there are infinitely many possible answers since it is possible to find a polynomial of degree 5 (or higher) that will go through each of the above numbers and ANY other number, missing from ANY position.Using polynomials of order 4, though, there is only one answer for each position. For example,First number missing: 171Un= (-27n4+ 422n3- 2364n2+ 5611n - 4668)/6Last number missing: 218Un= (-27n4+ 314n3- 1260n2+ 2041n - 1026)/6The answer will depend on where, in the sequence, the missing number is meant to be. Also, in each case, there are infinitely many possible answers since it is possible to find a polynomial of degree 5 (or higher) that will go through each of the above numbers and ANY other number, missing from ANY position.Using polynomials of order 4, though, there is only one answer for each position. For example,First number missing: 171Un= (-27n4+ 422n3- 2364n2+ 5611n - 4668)/6Last number missing: 218Un= (-27n4+ 314n3- 1260n2+ 2041n - 1026)/6The answer will depend on where, in the sequence, the missing number is meant to be. Also, in each case, there are infinitely many possible answers since it is possible to find a polynomial of degree 5 (or higher) that will go through each of the above numbers and ANY other number, missing from ANY position.Using polynomials of order 4, though, there is only one answer for each position. For example,First number missing: 171Un= (-27n4+ 422n3- 2364n2+ 5611n - 4668)/6Last number missing: 218Un= (-27n4+ 314n3- 1260n2+ 2041n - 1026)/6