Assuming the spinner has sections numbered 1-5 then:
Pr(Spin < 4) = 3/5 (= 0.6 or 60%)
Pr(Roll > 4) = 3/6 = 1/2 (= 0.5 or 50%)
Assuming both done together:
Pr(spin < 4 or roll < 4)
= Pr(spin < 4) + Pr(roll < 4) - Pr(spin < 4 and roll < 4 [at same time])
= 3/5 + 1/2 - 3/5 × 1/2
= 6/10 + 5/10 - 3/10
= 8/10
= 4/5 (= 0.8 or 80%)
It can also be calculated out by working out the probability of not spinning less than 4 and not rolling less than 4 (at the same time), and then subtracting this from 1 (or 100%):
Pr(spin < 4 or roll < 4)
= 1 - Pr(spin ≥ 4 and roll ≥ 4)
= 1 - (1 - 3/5) x (1 - 1/2)
= 1 - 2/5 x 1/2
= 1 - 1/5
= 4/5 (= 0.8 or 80%)
The probability of spinning the spinner and landing on an odd number depends on the number of odd numbers on the spinner and the total number of numbers on the spinner. If there are 3 odd numbers on the spinner and a total of 6 numbers, then the probability of landing on an odd number is 3/6, which simplifies to 1/2 or 50%.
Assuming that the four-sided spinner is fair and that it is numbered in the traditional way of 1, 2, 3 and 4, the probability of spinning a three is 1/4.
The depends on what other numbers exist on the spinner. If there are a total of six numbers on the spinner, for instance, the probability of spinning a 1-4 is 2 in 3.
The answer depends on what the experiment is: drawing a card, rolling a die, with a spinner, ...The answer depends on what the experiment is: drawing a card, rolling a die, with a spinner, ...The answer depends on what the experiment is: drawing a card, rolling a die, with a spinner, ...The answer depends on what the experiment is: drawing a card, rolling a die, with a spinner, ...
0.75%
Assuming each possible number on a spinner has the same probability and an unbiased die is being rolled, the answer depends on how many numbers are on the spinner, and how many times the number 4 appears on each.To find the probability, workout the probability of spinning a 4 on the spinner and the probability of rolling a 4 on the die; then as spinning the spinner has no effect on rolling the die, they are independent events and to get the probability of both happening multiply them together.The probability of success is the number of successful outcomes divided by the total number of outcomes, giving:Probability(spinning a 4) = how_many_4s_are_on_the_spinner / how_many_numbers_are_on_the_spinnerProbability(rolling a 4) = how_many_4s_are_on_the_die / how_many_numbers_are_on_the_dieProbability(spinning a 4 and rolling a 4) = Probability(spinning a 4) × Probability(rolling a 4)Examples:an octagonal spinner with the numbers 1-4 on it each twice and a tetrahedral die (as used in D&D games) with the numbers 1-4 on it→ pr(spin 4 & roll 4) = 2/8 × 1/4 = 1/16a decagonal spinner with the numbers 0-9 and a tetrahedral die with the numbers 0-3 on it→ pr(spin 4 & roll 4) = 1/10 × 0/4 = 0a decagonal spinner with the numbers 0-9 and a standard die with the numbers 1-6 on it→ pr(spin 4 & roll 4) = 1/10 × 1/6 =1/60
The answer depends on the shape of the spinner and the numbers on it.
The probability of spinning the spinner and landing on an odd number depends on the number of odd numbers on the spinner and the total number of numbers on the spinner. If there are 3 odd numbers on the spinner and a total of 6 numbers, then the probability of landing on an odd number is 3/6, which simplifies to 1/2 or 50%.
The answer depends on the shape of the spinner.
independent
Assuming that the four-sided spinner is fair and that it is numbered in the traditional way of 1, 2, 3 and 4, the probability of spinning a three is 1/4.
The depends on what other numbers exist on the spinner. If there are a total of six numbers on the spinner, for instance, the probability of spinning a 1-4 is 2 in 3.
The answer will depend on the patter of colours on the two spinners.
If it is a fair spinner, then 3/8
The answer depends on what the experiment is: drawing a card, rolling a die, with a spinner, ...The answer depends on what the experiment is: drawing a card, rolling a die, with a spinner, ...The answer depends on what the experiment is: drawing a card, rolling a die, with a spinner, ...The answer depends on what the experiment is: drawing a card, rolling a die, with a spinner, ...
1/6
0.75%