Assuming each possible number on a spinner has the same probability and an unbiased die is being rolled, the answer depends on how many numbers are on the spinner, and how many times the number 4 appears on each.
To find the probability, workout the probability of spinning a 4 on the spinner and the probability of rolling a 4 on the die; then as spinning the spinner has no effect on rolling the die, they are independent events and to get the probability of both happening multiply them together.
The probability of success is the number of successful outcomes divided by the total number of outcomes, giving:
Probability(spinning a 4) = how_many_4s_are_on_the_spinner / how_many_numbers_are_on_the_spinner
Probability(rolling a 4) = how_many_4s_are_on_the_die / how_many_numbers_are_on_the_die
Probability(spinning a 4 and rolling a 4) = Probability(spinning a 4) × Probability(rolling a 4)
Examples:
The probability of (1 or 2 or 3) on the first (or any) roll is 1/2 = 50% .The probability of (4 or 5 or 6) on the second (or any) roll is 1/2 = 50% .The probability of exactly that result on two rolls is (1/2 x 1/2)= (50% x 50%) = 1/4 = 25% .
The probability of 1 roll of 4 rolls of a die being 6 is: 1/6 x 5/6 x 5/6 x 5/6 = 125/1296 However, that one roll could be the first, second, third or fourth roll, so the total probability is 4 times this: Pr(one 6 on 4 rolls of 1 die) = 4 x 125/1296 = 125/324 ≈ 0.385
You can roll (3,6), (4,5), (5,4), or (6,3). So that's four possibilities out of 36. So 4/36 or 1/9.
2/3
1/3
Assuming the spinner has sections numbered 1-5 then: Pr(Spin < 4) = 3/5 (= 0.6 or 60%) Pr(Roll > 4) = 3/6 = 1/2 (= 0.5 or 50%) Assuming both done together: Pr(spin < 4 or roll < 4) = Pr(spin < 4) + Pr(roll < 4) - Pr(spin < 4 and roll < 4 [at same time]) = 3/5 + 1/2 - 3/5 × 1/2 = 6/10 + 5/10 - 3/10 = 8/10 = 4/5 (= 0.8 or 80%) It can also be calculated out by working out the probability of not spinning less than 4 and not rolling less than 4 (at the same time), and then subtracting this from 1 (or 100%): Pr(spin < 4 or roll < 4) = 1 - Pr(spin ≥ 4 and roll ≥ 4) = 1 - (1 - 3/5) x (1 - 1/2) = 1 - 2/5 x 1/2 = 1 - 1/5 = 4/5 (= 0.8 or 80%)
1/6 for all 6 numbers.-- On the first roll, the probability of a ' 1 ' is 1/6 .-- On the second roll, the probability of a ' 2 ' is 1/6 .-- On the third roll, the probability of a ' 3 ' is 1/6 .-- On the fourth roll, the probability of a ' 4 ' is 1/6 .-- On the fifth roll, the probability of a ' 5 ' is 1/6 .-- On the sixth roll, the probability of a ' 6 ' is 1/6 .So the probability of rolling 1 - 2 - 3 - 4 - 5 - 6 in six rolls is (1/6)6 = 0.000021433 = 0.0021%
If you roll a single die (cube), the probability of a 4 is 1/6 or 162/3%. If you roll a pair of dice (2 cubes), the probability of a 4 is 1/12 or 82/3%.
The answer depends on the shape of the spinner.
If you roll the die often enough, the probability is 1 - a certainty.On a single roll, the probability is 1/6.If you roll the die often enough, the probability is 1 - a certainty.On a single roll, the probability is 1/6.If you roll the die often enough, the probability is 1 - a certainty.On a single roll, the probability is 1/6.If you roll the die often enough, the probability is 1 - a certainty.On a single roll, the probability is 1/6.
1/12
It is 1/6.
one out of 6
It is 1 (a certainty) if you roll it often enough. For a single roll of a fair die, the probability is 1/6.
Let say the dice has n sides Let first search for the probability to roll a number less or equal to 2 Probability to roll a 1 = 1/n Probability to roll a 2 = 1/n Probability to roll a 1 OR a 2 = Probability to roll a 1 + Probability to roll a 2 = 1/n + 1/n = 2/n Probability to roll a number greater than 2 = 1 - (Probability to roll a 1 OR a 2) = 1 - 2/n = (n-2)/n If n = 6 then the result is (6-2)/6 = 4/6 = 2/3
The probability is 1/6.
The probability of rolling either a 6 or 4 on one roll of a dice is two thirds (one sixth plus one sixth because both four and six have a probability of one sixth.