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What is the probability of spinning a free on one spin and an s on your second if you have a spinner with 1 space labeled free and the remaining 11 Mississippi with one letter in each.?
What_is_the_probability_of_spinning_a_free_on_one_spin_and_an_s_on_your_second_if_you_have_a_spinner_with_1_space_labeled_free_and_the_remaining_11_mississippi_with_one_letter_in_each.So, you would multiply 1/12 times 4/12 to get 4/144 or 1/36
If a spinner is divided into 4 equal parts 2 colored blue one green and one red what is the probability that you would spin a blue?
The chance of receiving a blue result is 2 in 4, in other words 50%.
If yellow equals one fourth what would the probability of spinning a yellow 50 times?
1/4 raised to the power of 50; e.g. .2550.
What is the probability of spinning a number greater than 2 on a six sectioned spinner numbered 1-6?
4/6, or 66.67%.
What are the probabilities of spinning red green yellow and blue if a spinner is divided equally into those four colors?
Assuming you want the probability FOR A SINGLE TRY, and you want the numbers in that exact order, the probability for each part (for instance, first = red; or second = green) is 1/4; therefore, the probability for the combination is (1/4) to the power 4.
What is the probability of spinning a blue and then a red or a yellow there are four colors on the board?
If there are four colors on a spinner, then the probability of spinning one particular color is 1 in 4, or 0.25. Also, the probability of spinning one of two particular colors is 2 in 4, or 0.5. Combining these two "unrelated" events simply requires multiplication. The probability, then, of spinning one particular color on one spin, and then spinning one of two particular colors on the next spin is (1 in 4) times (2 in 4), or 2 in 16, or 0.125.
What is the propability of not spinning 4 with one spin?
The probability is 5/6. The die has 6 sides so 5 of them are not the "4". The probability of getting the four is 1/6.
What is the probability that you will spin a 4 and roll a 4?
Assuming each possible number on a spinner has the same probability and an unbiased die is being rolled, the answer depends on how many numbers are on the spinner, and how many times the number 4 appears on each.To find the probability, workout the probability of spinning a 4 on the spinner and the probability of rolling a 4 on the die; then as spinning the spinner has no effect on rolling the die, they are independent events and to get the probability of both happening multiply them together.The probability of success is the number of successful outcomes divided by the total number of outcomes, giving:Probability(spinning a 4) = how_many_4s_are_on_the_spinner / how_many_numbers_are_on_the_spinnerProbability(rolling a 4) = how_many_4s_are_on_the_die / how_many_numbers_are_on_the_dieProbability(spinning a 4 and rolling a 4) = Probability(spinning a 4) × Probability(rolling a 4)Examples:an octagonal spinner with the numbers 1-4 on it each twice and a tetrahedral die (as used in D&D games) with the numbers 1-4 on it→ pr(spin 4 & roll 4) = 2/8 × 1/4 = 1/16a decagonal spinner with the numbers 0-9 and a tetrahedral die with the numbers 0-3 on it→ pr(spin 4 & roll 4) = 1/10 × 0/4 = 0a decagonal spinner with the numbers 0-9 and a standard die with the numbers 1-6 on it→ pr(spin 4 & roll 4) = 1/10 × 1/6 =1/60
There are 4 numbers the probability of spinning the number 3 is what?
The probability of spinning the number 3, or any number, is 1/4 or 0.25 since there is 4 numbers total.
What is the probability of spinning a free on one spin and an s on your second if you have a spinner with 1 space labeled free and the remaining 11 Mississippi with one letter in each.?
What_is_the_probability_of_spinning_a_free_on_one_spin_and_an_s_on_your_second_if_you_have_a_spinner_with_1_space_labeled_free_and_the_remaining_11_mississippi_with_one_letter_in_each.So, you would multiply 1/12 times 4/12 to get 4/144 or 1/36
What is the probability of getting a head when spinning 2 coins?
Just one head = 2/4 = 1/2
What is the probability of spinning a 3 on a four sided spinner?
Assuming that the four-sided spinner is fair and that it is numbered in the traditional way of 1, 2, 3 and 4, the probability of spinning a three is 1/4.
If a spinner is divided into 4 equal parts 2 colored blue one green and one red what is the probability that you would spin a blue?
The chance of receiving a blue result is 2 in 4, in other words 50%.
What are the chances of spinning a 4 from 1 2 3 4 5 and 6?
On one spin, and assuming the spinner is fair, 1/6
What is the probability of not spinning a 4 on a spinner with ten spaces labeled 1-10?
0.75%
If you spin the spinner two times what is the probability that the spinner will land on the black region twice?
To calculate the probability of spinning the black region twice on a spinner, you first need to determine the total number of possible outcomes when spinning the spinner twice. Let's say the spinner has 8 equal sections, with 2 black regions. The total outcomes for spinning the spinner twice would be 8 x 8 = 64. The probability of landing on the black region twice would be 2/8 x 2/8 = 4/64 = 1/16. Therefore, the probability of landing on the black region twice is 1/16 or approximately 0.0625.
If yellow equals one fourth what would the probability of spinning a yellow 50 times?
1/4 raised to the power of 50; e.g. .2550.
