The first thing to do is isolate how many ways there are to get 8 from two dice. These possibilities are:
2,6
3,5
4,4
5,3
6,2
so there are 5 possibilities. The probability of each of these combinations is (1/6)2 or 1/36, so the probability of getting 8 in one throw of 2 dice is 5/36
For 9 throws, it is easier to calculate the probability of never getting 8. This is (1-probability of getting 8)9. (1-5/36)9 = (31/36)9 which is 0.26033. So the probability of getting an 8 somewhere along the line is 1-0.26033 or 0.7397
If you were throwing one numbered cube (dice) with each face numbered 1 to 6, then the chance of getting a number greater than two is 4/6 (or 2/3) since there are 4 numbers greater than 2, and six numbers in total.Similarly, if you were throwing one dice, the chance of getting a number less than 2 is 1/6.To determine the probability of getting both of these outcomes on two dice (greater than 2 on one dice and less than 2 on the other) we simply multiply these two values together.2/3 x 1/6 = 2/18 = 1/9.So there is a one in nine chance of this outcome occuring.
Q1: You can have a die and many dice, but what is "a dice"? Q2: A 9-sided die cannot be a regular polyhedron. With an irregular polyhedron some outcomes are more likely than others. What is the shape? Q3: Since there are 2606 different (non-isomorphic) 9-sided dice possible and each one will have a different probability distribution, how will you determine the probability distribution function for the faces on your die? Q4: What are the numbers on the faces? Are they 1-9 or some other set, such as for a doubling die in backgammon? Once you have got your answers to the above you can start thinking about the probability distribution function for the different numbers on the die. Then you can look at questions regarding multiple rolls.
A single roll of 2 dice can come up in (6 x 6) = 36 ways. A sum of five is made with 1 and 4, 4 and 1 2 and 3, 3 and 2 four out of the 36. The probability is (4/36)= 1/9 on each roll. If each roll is perfectly random, then the probability of getting a 5 in 9 rolls is 100%.
The probability of rolling a nine or higher with one pair of dice is 10 in 36, or 5 in 18, or about 0.2778. Out of the 36 possible permutations, the 10 that match the criteria are (6-3) (5-4) (4-5) (3-6) (6-4) (5-5) (4-6) (6-5) (5-6) (6-6).
Here are the ways of rolling the dice that satisfy those conditions: 1 1 1 2 2 1 4 6 5 5 5 6 6 4 6 5 6 6 There are nine possibilities out of 36, hence, the probability is 9/36 = 1/4.
Throwing two dice, there are a total of 36 combinations (1-1, 1-2, 1-3, etc.), each of which has the same probability. Of these, the following give a sum of nine: 3-6, 4-5, 5-4, 6-3. That makes four favorable cases, or a probability of 4/36.
50%
There are 36 permutations of two standard dice. Of these, four have a sum of nine, specifically 3+6, 4+5, 5+4, and 6+3. The probability, then, of rolling a nine on a pair of standard dice is 4 in 36, or 1 in 9, or about 0.1111.
There are twenty six ways out of thirty six possible rolls of two dice to hit a number less than nine OR a seventy two percent probability.
There are nine possible successes:1 - 55 - 12 - 44 - 23 - 33 - 66 - 34 - 55 - 4The probability of success = 9/36 = 0.25 = 25%
100%, since you cannot roll a 9 with a six sided die.
If you were throwing one numbered cube (dice) with each face numbered 1 to 6, then the chance of getting a number greater than two is 4/6 (or 2/3) since there are 4 numbers greater than 2, and six numbers in total.Similarly, if you were throwing one dice, the chance of getting a number less than 2 is 1/6.To determine the probability of getting both of these outcomes on two dice (greater than 2 on one dice and less than 2 on the other) we simply multiply these two values together.2/3 x 1/6 = 2/18 = 1/9.So there is a one in nine chance of this outcome occuring.
Q1: You can have a die and many dice, but what is "a dice"? Q2: A 9-sided die cannot be a regular polyhedron. With an irregular polyhedron some outcomes are more likely than others. What is the shape? Q3: Since there are 2606 different (non-isomorphic) 9-sided dice possible and each one will have a different probability distribution, how will you determine the probability distribution function for the faces on your die? Q4: What are the numbers on the faces? Are they 1-9 or some other set, such as for a doubling die in backgammon? Once you have got your answers to the above you can start thinking about the probability distribution function for the different numbers on the die. Then you can look at questions regarding multiple rolls.
A single roll of 2 dice can come up in (6 x 6) = 36 ways. A sum of five is made with 1 and 4, 4 and 1 2 and 3, 3 and 2 four out of the 36. The probability is (4/36)= 1/9 on each roll. If each roll is perfectly random, then the probability of getting a 5 in 9 rolls is 100%.
D9
You can roll (3,6), (4,5), (5,4), or (6,3). So that's four possibilities out of 36. So 4/36 or 1/9.
6 & 4 And 5 & 5 are the only two possibilities, so 4 chances in 36 or 1 in nine.