Depends on how many dice are involved.
1 die 1/6
2 dice 1/3
3 dice 1/2
It is 0.8181... recurring.
It is 2/11.
It is 0.9459
50%. There are three dice; each die has 6 faces.
When rolling two number cubes (standard six-sided dice), the probability of not rolling a six on a single die is 5/6. Therefore, the probability of not rolling a six on both dice is (5/6) × (5/6) = 25/36. To find the probability of rolling at least one six, we subtract this result from 1: 1 - 25/36 = 11/36. Thus, the probability of rolling at least one six when rolling two dice is 11/36.
The probability of getting at least one prime number in two dice is 3/4.
With one roll of three dice, the probability is 7/8.
It is 0.8181... recurring.
5/36
9/11
When rolling one die, the probability of getting a 4 is 1 in 6, or 0.1667. If two dice are rolled, you get two unrelated chances of rolling at least one 4, so the probability is 2 in 6, or 0.3333.
It is 7/8.
It is 2/11.
The probability of rolling at least one '1' with six dice is 66.5% [1-(5/6)^6]*100%
It is 0.9459
50%. There are three dice; each die has 6 faces.
I suppose you mean, at least one of those numbers. Just calculate the probability of NOT getting any of those, and take the complement. The probability of not getting a one nor a five on a single die is 4/6 or 2/3. For two dice, the probability is 2/3 x 2/3 = 4/9. So, the probability of getting at least a one or a five with two dice is 1 - 4/9 = 5/9.I suppose you mean, at least one of those numbers. Just calculate the probability of NOT getting any of those, and take the complement. The probability of not getting a one nor a five on a single die is 4/6 or 2/3. For two dice, the probability is 2/3 x 2/3 = 4/9. So, the probability of getting at least a one or a five with two dice is 1 - 4/9 = 5/9.I suppose you mean, at least one of those numbers. Just calculate the probability of NOT getting any of those, and take the complement. The probability of not getting a one nor a five on a single die is 4/6 or 2/3. For two dice, the probability is 2/3 x 2/3 = 4/9. So, the probability of getting at least a one or a five with two dice is 1 - 4/9 = 5/9.I suppose you mean, at least one of those numbers. Just calculate the probability of NOT getting any of those, and take the complement. The probability of not getting a one nor a five on a single die is 4/6 or 2/3. For two dice, the probability is 2/3 x 2/3 = 4/9. So, the probability of getting at least a one or a five with two dice is 1 - 4/9 = 5/9.