2y2
No.
2 * 7 * x * x * y
The GCF is 15x^2y^2
To write this algebraically: 7(y^3)|y = 2 Substitute 2 for y: 7(2^3) 2^3 = 8, so substitute 8 for (2^3): 7*8 = 56
You're asking: x*y = 12 x/y = 3 Well, from the second equation, x = 3y Plug that into the first, 3y2 = 12, y2 = 4, y = 2 Plug that y into the second, x = 3*2 = 6
No.
2 * 7 * x * x * y
If ' y ' is greater than ' 1 ', then [ 3y to the second power ] is. If ' y ' is less than ' 1 ', then 3 is.
Its (x-2)to the second power +(y-v) to the second power=r2
The GCF is 15x^2y^2
(y2/81)1/2 = y/9
(x+y)^2+z^2=x^2+y^2+z^2+2xy or ((x+y)^2+z)^2= (x^2+y^2+2xy+z)^2= x^4+y^4+z^2+6x^2y^2+4x^3y+2x^2z^2+4xy^3+4xyz^2+2z^2y^2
To write this algebraically: 7(y^3)|y = 2 Substitute 2 for y: 7(2^3) 2^3 = 8, so substitute 8 for (2^3): 7*8 = 56
You're asking: x*y = 12 x/y = 3 Well, from the second equation, x = 3y Plug that into the first, 3y2 = 12, y2 = 4, y = 2 Plug that y into the second, x = 3*2 = 6
To square a number or an entire segment with variables, parenthesize the particular section and write a square power outside. In this case, it is (12xy)^2. In expanded form, it is 144 . x^2 . y^2 .
-8
15