No.
(Y squared) minus (2 times Y) minus 15 = 0. The left side can be factored into: (Y - 5)(Y + 3) There are two different values for Y that will work for the above equation.
(xy - 7)(x^2y^2 + 7xy + 49)
y² - y - 6 = (y + 2)(y - 3)
-y minus 12 is 12.
No.
If you multiplied all the terms by y2, you could simplify this to -3y3.
15
(Y squared) minus (2 times Y) minus 15 = 0. The left side can be factored into: (Y - 5)(Y + 3) There are two different values for Y that will work for the above equation.
(xy - 7)(x^2y^2 + 7xy + 49)
y² - y - 6 = (y + 2)(y - 3)
-y minus 12 is 12.
The vertex is (5, 11).
short answer 26 and 49 long answer let x = the first number let y = the second number x + y = 75 y = 2x - 3 substitute y into the first equation x + 2x - 3 = 75 3x = 78 x = 26 use the second equation to find y y = 2(26) - 3 y = 52 - 3 y = 49
y2-y-72 is an algebraic expression that can be factored as: (y+8)(y-9)
That is the English alphabet, minus the letters i, k, l, n, and u, with a second y where u should be.
y2-4y-32 = (y+4)(y-8) when factored