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No.
(Y squared) minus (2 times Y) minus 15 = 0. The left side can be factored into: (Y - 5)(Y + 3) There are two different values for Y that will work for the above equation.
-y minus 12 is 12.
y² - y - 6 = (y + 2)(y - 3)
(xy - 7)(x^2y^2 + 7xy + 49)