(x+y)^2+z^2=x^2+y^2+z^2+2xy
or
((x+y)^2+z)^2=
(x^2+y^2+2xy+z)^2=
x^4+y^4+z^2+6x^2y^2+4x^3y+2x^2z^2+4xy^3+4xyz^2+2z^2y^2
-8
Assuming y' is dy/dx, y = x^4/4 + yx^2
The answer to Y x plus 5 Y 6 is Y(x+5Y5).One possible solution to y x plus 5 y 6 is Y(x+5Y5).
x^3+y^3 Cube root of the first, x plus cube root of the last, y times What it takes to make the first number, x^2 Opposite sign, - Product of the two cube roots, -xy Then what it takes to make the last. (x+y)(X^2-xy+y^2)
4
15
xy 2nd
If: y2+x2 = 52 Then: x2 = 52-y2 Their values could be: x = 3 and y = 4
... and what is the question?
999 and 1
y = x + ex then dy/dx = 1 + ex and d2y/dx2 = ex
It's an equation. Specifically, in 3 dimensions it's the equation of a right cone centered on the origin.
369
-8
X + Y⁶X + Y * Y * Y * Y * Y * Y
x2 + 121y2 = x2 - (-121)y2 = x2 - (11iy)2 = (x - 11iy)(x + 11iy)
The second