what is the formula to use to solve the product of two consecutive odd integers
The integers are 5 and 7.
9240 is the product of the three consecutive integers 20, 21, and 22.
There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.
The two consecutive positive integers whose product is 380 are 19 x 20.
There is no set of two consecutive integers having a product of 14. Product means the result of multiplication.
There are no two consecutive integers whose product is 421 - the product of 20 and 21 is 420.
The two consecutive odd integers having a product of 99 are 9 and 11.
The product of two consecutive integers is 132. Find the two integers. They are: 11*12 = 132
There is no set of two consecutive integers equating to 200.
Their product is 143.
There are no two consecutive integers, negative or positive, whose product is 440.
The integers are 9 and 10.
No, it is not. It is the sum of two consecutive integers: 46 and 47.
I think you mean consecutive even integers: 20 & 22
No, it is not.
35 and 37.
17 and 18.
10 and 12
56.25% is not an integer and so cannot be expressed as a sum, difference, product or quotient of consecutive integers.
You can solve this in two ways.1) Trial and error. That is, try multiplying two consecutive integers; if the product is too large, try smaller integers; if the product is too small, try larger consecutive integers. 2) Call the two consecutive integers "n" and "n+1", and solve the equation: n(n+1)=210
the two consecutive positive integers whose product is 380 19 20
The product of four consecutive integers is always one less than a perfect square. The product of four consecutive integers starting with n will be one less than the square of n2 + 3n + 1
The integers are -37, -36 and -35. Also, using consecutive even integers: -38, -36 and -34.
The two consecutive, odd integers whose product equals 143 are 11 and 13.