The two consecutive odd integers having a product of 99 are 9 and 11.
97 and 99
The numbers are 97, and 99.
98 & 99
All of them from 45 to 99 ... 55 integers.
The sum of 50 consecutive odd integers is equal to: (First Term + Last Term) * (The number of Terms)/2 or in this case, more specifically: (2 * First Term + 98) * 25 If you meant 1+3+5+7+...+99, then the sum is 2500.
99 = 9*11
97 and 99
They are: 97+99 = 196
31, 33, 35
97 + 99 = 196
9 and 11. 9x11=99
The two numbers are 9 and 11, or indeed -9 and -11. Therefore, the larger number is 11 (or -9).
97 x 99 x 101 = 969903
The integers are 49 and 50.
The numbers are 5, 7, 9, 11 (35 is 64 less than 99) The equation is (A)(A+2) = (A+4)(A+6) - 64 A2 + 2A = A2 +10A +24 -64 2A = 10A - 40 8A = 40 A = 5
The GCF of consecutive integers is 1.
32+33+34=99