X2 - 5X - 4 = 0
X = - b (+/-) sqrt(b2 - 4ac)/2a
a = 1
b = - 5
c = - 4
X = - ( - 5) (+/-) sqrt[(- 5)2 - 4(1)(- 4)]/2(1)
X = 5 (+/-) sqrt(25 + 16)/2
X = [5 (+/-) sqrt(41)]/2
-------------------------------------exact answer
If: x2+x = 12 Then: x2+x-12 = 0 And using the quadratic formula: x = -4 or x = 3
Using the quadratic equation formula:- x = 3.795831523 or x = -5.795831523
By using the quadratic equation formula: (4x+1)(x-3) = 0
In the generic formula, replace the coefficients a = 1, b = -2, c = -3.
No solution in integers, Quadratic formula gives roots as 1.78 and -0.28
(x - 3)(x + 1)
If: x2+x = 12 Then: x2+x-12 = 0 And using the quadratic formula: x = -4 or x = 3
Using the quadratic equation formula:- x = 3.795831523 or x = -5.795831523
By using the quadratic equation formula: (4x+1)(x-3) = 0
In the generic formula, replace the coefficients a = 1, b = -2, c = -3.
If you can't factor it easily, use the quadratic formula.
Use the quadratic equation formula to find the solutions to this equation.
No solution in integers, Quadratic formula gives roots as 1.78 and -0.28
If you can't factor it easily, use the quadratic formula.
2x2-10+7 = 0 Solving the quadratic equation using the quadratic formula will give you two solutions and they are: x = (5 - the square root of 11)/2 or x = (5 + the square root of 11)/2
Use the quadratic formula, with a = 1, b = -3, c = 2.
The first step is to show an example of the quadratic equation in question because the formula given is only the general form of a quadratic equation.