-2x2 + 9x - 12 = 0Then apply the quadratic formula.
x = - 4 - or + the square root of 3 Solved by using the quadratic equation formula.
Using the quadratic equation formula:- x = 1 +/- the sqrt of 13 = -2.60555 and 4.60555 (to 5 dp).
Taking the equation to be y=ax2 + bx +c , and using the formula x = -b plus/minus sqrt (b2-4ac), all over 2a: x = (-3+21)/12 or (-3-21)/12 so x = 1.5 or -2
(x-12)^2= 45 x^2 - 24x + 144 = 45 x^2 - 24x + 99 = 0 Using quadratic formula : (24 +/- (180)^0.5) / 2 In exact terms (using surds) = 12 +/- 3 x (5)^0.5 OR = 18.7 or 5.29
-2x2 + 9x - 12 = 0Then apply the quadratic formula.
Using the quadratic equation formula: x = 8.42 or x = -1.42
x = - 4 - or + the square root of 3 Solved by using the quadratic equation formula.
Using the quadratic equation formula:- x = 1 +/- the sqrt of 13 = -2.60555 and 4.60555 (to 5 dp).
Taking the equation to be y=ax2 + bx +c , and using the formula x = -b plus/minus sqrt (b2-4ac), all over 2a: x = (-3+21)/12 or (-3-21)/12 so x = 1.5 or -2
(x-12)^2= 45 x^2 - 24x + 144 = 45 x^2 - 24x + 99 = 0 Using quadratic formula : (24 +/- (180)^0.5) / 2 In exact terms (using surds) = 12 +/- 3 x (5)^0.5 OR = 18.7 or 5.29
x2+8x+12 = 0 When factorized: (x+6)(x+2) = 0 Therefore: x = -6 or x = -2
x2+10x+1 = -12+2x x2+10x-2x+1+12 = 0 x2+8x+13 = 0 Solving by using the quadratic equation formula: x = - 4 - or + the square root of 3
( x - 2)( x - 6) = 0 x = 2 or x = 6
2x2-2x=12x2-2x-1=0a=2 b=-2 c=-1x= (-b +- sqr(b2-4ac))/2ax= (2 +- sqr(4 + 8))/4x= (2 +- sqr(12))/4x = 1/2 +- sqr(12)/4x ~= .5 +- 0.8660x ~=-0.3660 or x ~= 1.3660
x2 + 24x +180 = 0 By using the quadratic equation, you can find that x = -12 + 6i or x = -12 - 6i
This quadratic expression can be arranged as: -x2+7x+12 When factorised: (-x+8.424428901)(x+1.424428901) So the intercepts are: x = 8.424428901 or x = -1.424428901 The above was worked out by using the quadratic equation formula.