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What is the quotient in polynomial form -1 2 7 5 A. x plus 5 B. x - 5 C. 2x - 5 D. 2x plus 5?
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How do you factor C squared X plus C squared Y?
C2x + C2y = C2(x + y)
What is the x-intercept of 2x plus 8y equals 40?
This form needed. Y = mX + c2X + 8Y = 408Y = - 2X + 40Y = - 1/4 + 5-----------------------zero out the Y- 1/4X + 5 = 0- 1/4X = - 5X = 20-------------------your X intercept
What is the x and y intercepts for 2x-3y24?
Put in this form. Y = mX + c2X - 3Y = 24- 3Y = - 2X + 24Y = 2/3X - 8-------------------zero out variables in turn2/3X - 8 = 02/3X = 8X = 12--------------------X interceptY = 2/3(0) - 8Y = - 8------------------------Y intercept(12, - 8)------------------answer
How do you factor C squared X plus C squared Y?
C2x + C2y = C2(x + y)
What is the x-intercept of 2x plus 8y equals 40?
This form needed. Y = mX + c2X + 8Y = 408Y = - 2X + 40Y = - 1/4 + 5-----------------------zero out the Y- 1/4X + 5 = 0- 1/4X = - 5X = 20-------------------your X intercept
Which point lies on 2x plus 5y equals 10?
First, in this form. Y =mX + c2X + 5Y = 105Y = - 2X + 10Y = (-2/5)X + 2Y = 2----------0 out equation(- 2/5)X + 2 = 0(- 2/5)X = - 2X = 5---------(0, 2) and (5, 0)------------------------------ points on the line
What is the equation written in standard form of 2X - y - 8 equals 0?
2X - y - 8 = 0the standard form of the equation is y = mx + chere you have to write the given equation in the standard form as in the form of y = mx + c2X - y - 8 = 0 - y -8 = -2x-y = -2x +8y = 2x -8so the standard form of the given equation is y = 2x - 8
What is the x and y intercepts for 2x-3y24?
Put in this form. Y = mX + c2X - 3Y = 24- 3Y = - 2X + 24Y = 2/3X - 8-------------------zero out variables in turn2/3X - 8 = 02/3X = 8X = 12--------------------X interceptY = 2/3(0) - 8Y = - 8------------------------Y intercept(12, - 8)------------------answer
Is it ok to use the same random number again while signing two messages m1 and m2 using schnorr signature?
Ok here is the answer u r looking for. You cannot use the same random number twice because it will lead the adversary in to finding the secret key x.For the first time r1 = gk1 mod pc1 = H(m1,r1)s1 = k1 + c1x (mod q)----- eqn 1output is (r1, s1,m1)For the second time r1 = r2 = gk1 mod p c2 = H(m2,r1) s2 = k1 + c2x (mod q)-----eqn 2 output is (r1, s2, m2)eqn1-eqn2 s1-s2=c1x (mod q) - c2x (mod q) s1-s2=x modq (c1- c2) x mod q = s1-s2/c1-c2 s1,s2,c1,c2 and q are known.
How would you Write an equation that passes through the point 6 5 and is parallel to the line whose equation is 2x 3y equals 11?
ax+by=c2x+3y=113y=-2x+11(3y=-2x+11)/3= y=-2/3x+11/3 slope intercept form5=-2/3(6)+b replace x and y with point given5=-4+b9=bthereforey=-2/3x+92x+3y=27
What is the slope of the line that is perpendicular to the line whose equation is 2x y 4?
The product of the slope of a line with the slope of a line perpendicular to it is -1.Or to put it another way, if a line has an equationy = mx + ca line perpendicular to it will have a gradient m' such thatmm' = -1⇒ m' = -1/mand an equation ofy = -1/m x + bwhich can be rearranged to givemy + x = d(where d = mb).There are symbols missing from the question, which I suspect are a plus (+) and an equals (=). They can be inserted in two different ways, leading to two different solutions:2x + y = 4⇒ y = -2x + 4 ⇒ gradient of perpendicular line is -1/-2 = 1/2⇒ perpendicular line is:y = 1/2 x + b⇒ 2y = x + c2x = y + 4⇒ y = 2x - 4 ⇒ gradient of perpendicular line is -1/2 = -1/2⇒ perpendicular line is:y = -1/2 x + b⇒ 2y + x = cNote: there is no one perpendicular line, the value of the constant c will vary depending upon what point the line must pass through.
