Best Answer

oo=infinite limx->(+/-)oo(2x2+3)=oo

y=2x2+3

y'=4x=0

x=0 <-Location of absolute minimum

y(0)-2(0)2+3

y(0)=3

[3,oo)

Q: What is the range of 2x squared plus 3?

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The answer is (2x^2+3)(4x+1)

2x2+5x+3 = (2x+3)(x+1) when factored

(2x-3)(x-1)

(2x - 1)(x + 3)

8x3 + 4x2 + 6x + 3 = 4x2(2x + 1) + 3(2x + 1) = (2x + 1)(4x2 + 3)

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The answer is (2x^2+3)(4x+1)

2x2+5x+3 = (2x+3)(x+1) when factored

(2x-3)(x-1)

(2x - 1)(x + 3)

8x3 + 4x2 + 6x + 3 = 4x2(2x + 1) + 3(2x + 1) = (2x + 1)(4x2 + 3)

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