3(x2 + 3x + 1)
(x + 12)(x - 3)
Factor as : (x+9)(x+10) using the first terms ( x terms) multiply to x2; the last terms multiply to 90; the sum of 9x + 10 x = 19x
9x2+2x-7 = (9x-7)(x+1) when factored
In one bracket, write 16 times the square root of 2 minus 3x. In the other one, write 16 times the square root of 2 plus 3x.
3(2x - 3)(x + 3)
Assuming it's a plus sign, that factors to (2x + 1)(x + 4)
If you mean: 2x^2 +9x +7 then it is (2x+7)(x+1) when factored
2x2 - 9x + 10 = 2x2 - 4x - 5x + 10 = 2x(x - 2) - 5(x - 2) = (x - 2)(2x - 5)
(x + 3)(3x - 2)
9x2 - 18x + 99(x2 - 2x + 1)==========
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
(2x+3)(x+3)
2x2+9x+9 = (2x+3)(x+3) when factored
2x2-9x+4 = (2x-1)(x-4) when factored
(6x^3-9x^2) / (2x-3) = 3x^2((2x-3) / (2x-3) = 3 x ^2 (3 x squared)
10 + 9x