(2x+3)(x+3)
9x - 3(x + 13y) = 9x - 3x - 39y = 6x - 39y = 3(2x - 13y)
x + 20 + 10x = 20 + 9x 11x + 20 = 20 + 9x Subtract 20 from both sides: 11x = 9x Subtract 9x from both sides: 2x = 0 Divide both sides by 2: x = 0
2x^3-3x^2-11x+7x+32x^2-9x+16 R -41x+3 l 2x^3-3x^2-11x+7-(2x^3+6x^2)-9x^2-11x+7-(-9x^2-27x)16x+7-(16x+48)-412x^2-9x+16-[41/(x+3)]
the answer is (3x-2)(9x squared+6x+4)
Equation: 9X-3+4X=-2X You are going to want to factor this equation into something that looks like X=35, 35 being a randomly selected number. Step 1) Add 3 to both sides 9X+4X=-2X+3 Step 2) Add 2X to both sides 9X+4X+2X=3 Step 3) Simplify 15X=3 Step4) Divide both sides by 15 X=3/15
Assuming it's a plus sign, that factors to (2x + 1)(x + 4)
2x2+9x+9 = (2x+3)(x+3) when factored
2x2-9x+4 = (2x-1)(x-4) when factored
(2x+3)(x+3)
If you mean: 2x^2 +9x +7 then it is (2x+7)(x+1) when factored
Use the quadratic formula. x = -4.265564 or -0.234436
3(2x - 3)(x + 3)
2x2 - 9x + 10 = 2x2 - 4x - 5x + 10 = 2x(x - 2) - 5(x - 2) = (x - 2)(2x - 5)
2x + ? = 9x9x - 2x = 7xso...2x + 7x = 9x
9x2 - 18x + 99(x2 - 2x + 1)==========
3x^(2) +9x - 2x -6 Collect 'like terms'. Hence 3x^(2) + 7x - 6 Next write down all the factors of '3' and '6' Hence 3 ; 1' & 3' 6 ; 1,6 ; 2,3. From these pairs of number we select a pair from each coefficient, that add/multiply to '7' . Hence (3' x 3 ) & (1' x 2) ; NB 'dashes' (') to indicate source of numbers. Write up brackets (3x 2)(x 3) -2)(x + 3) Next we notice that the '6' is negative, so the two signs are different (+/-) The '7x' is positive , so the larger number takes the positive sign . Hence (3x - 2)(x + 3)
(9x)2 +9x/(45x)2 +81= 9+9x/86