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The range depends on the domain. If the domain is the complex field, the range is also the whole of the complex field. If the domain is x = 0 then the range is 4.
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What are the zeros of x2-2x-4?
Write it as x2 - 2x - 4 = 0, and solve with the quadratic formula (a = 1, b = -2, c = -4).
One factor of x2-2x-24 is?
x2-2x-24 when factorised = (x+4)(x-6)
Factor the polynomial expression x2 - 2x - 24?
x2 - 2x - 24 = (x - 6)(x + 4)
How do you factor completely x to the sixth power minus 64?
(x - 2)(x + 2)(x2 - 2x + 4)(x2 + 2x + 4)
X3 plus x2 minus 6x plus 4?
x3 + x2 - 6x + 4 = (x - 1)(x2 + 2x - 4)
How do you find the range of the function with the given domain?
The domain of the function 1/2x is {0, 2, 4}. What is the range of the function?
What is x2 4x 4?
(x2+3x-4) (x-4)
What is 2x to the power of 6 minus 128?
2(x + 2)(x - 2)(x2 + 2x + 4)(x2 - 2x + 4)
What are the zeros of x2-2x-4?
Write it as x2 - 2x - 4 = 0, and solve with the quadratic formula (a = 1, b = -2, c = -4).
One factor of x2-2x-24 is?
x2-2x-24 when factorised = (x+4)(x-6)
Factor the polynomial expression x2 - 2x - 24?
x2 - 2x - 24 = (x - 6)(x + 4)
What is 4xsquared 8x - 24 factored?
If that's + 8x, the answer is 4(x2 + 2x - 6) If that's - 8x, the answer is 4(x2 - 2x - 6)
What must be added to make x² - 2x plus 5 a perfect square?
negative four: x2 - 2x + 5 = x2 - 2x + 5 - 4 = x2 - 2x + 1 = (x - 1)2
How do you factor completely x to the sixth power minus 64?
(x - 2)(x + 2)(x2 - 2x + 4)(x2 + 2x + 4)
X3 plus x2 minus 6x plus 4?
x3 + x2 - 6x + 4 = (x - 1)(x2 + 2x - 4)
Quotient and remainder of 3X4 plus 2X3 minus X2 minus x minus 6 divided by X2 plus 1?
(3x4 + 2x3 - x2 - x - 6)/(x2 + 1)= 3x2 + 2x - 4 + (-3x - 2)/(x2 + 1)= 3x2 + 2x - 4 - (3x + 2)/(x2 + 1)where the quotient is 3x2 + 2x - 4 and the remainder is -(3x + 2).
Define one-to-one function?
the function (x),sory I can`t use the sign of the function because it is not available. the function of (x)=4x+4 is one to one function assume function(x1)= function(x2) then 4(x1)+4 =4(x2)+4 4(x1)=4(x2) (x1)=(x2) hence,the function is one to one
