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Q: X3 plus x2 minus 6x plus 4?

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x3 + 4x2 + 6x + 24 = (x2 + 6)(x + 4)

-x(x2 - 2)(x2 + 3)

x3 - 7x2 + 6x = x(x2 - 7x + 6) = x(x2 - x - 6x + 6) = x[x(x - 1) - 6(x - 1)] = x2(x - 1) - 6x(x - 1) = (x2 - 6x)(x - 1)

With great difficulty not knowing if 6x and 27 are plus or minus

(x2 plus 40) (x minus 1)

x3 - 7x2 + 6x =x (x2 - 7x + 6) =x (x - 6) (x - 1)

x3-x2

x3 + 3x2 - 6x - 8 = (x - 2)(x2 + 5x + 4) = (x - 2)(x + 1)(x + 4)

(x - 4)(x - 2)

x4 - 1.We can not "solve" this as we have not been told the value of x. However, we can simplify this expression:We have an x and a minus x here which will cancel out. Likewise the x2 and x3 will cancel out with the -x2 and -x3 respectively. This therefore leaves us with just x4 - 1.

x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)

16 + 6x - x2 = 16 + 8x - 2x - x2 = 8*(2 + x) - x*(2 + x) = (8 - x)*(2 + x)

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