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Q: What is the ratio of child tickets sold to adult tickets sold in raging waters?
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A charity sells tickets for a fund raising dinner Each adult's ticket costs 10 and each child's ticket costs 5 A total of 1050 was raised by selling 130 tickets How many adult and child tickets?

10 adults & 10 children's


At a basketball game adult tickets were sold at 7.50 each and student tickets at 3.50 each if 205 were sold and 1317.50 was collected how many tickets if each kind were sold?

The formula to determine the total money is nA + mC = 1317.50 where n is the number of adult tickets sold and A is the price of the adult tickets and m OS the number of child tickets and C is the price of a child ticket. Substituting in the actual prices we get... eq 1. n*7.50 + m * 3.50 = 1317.50 eq 2. n+m = 205 rearranging eq 2 we get n = 205 - m substituting this into eq 1 we get.. (205 -m) * 7.5 + m * 3.5 = 1317.50 Simplifying we get 1537.5 - 7.5m + 3.5m = 1317.50 1537.5 - 1317.5 = 4m 220 = 4m 55 = m substituting into eqn 2 we get n + 55 = 205 n = 150. Therefor 150 Adult tickets were sold 55 Child tickets were sold


Sam took his family to the zoo an adults ticket is two times the cost of a child's ticket the total cost for two adults tickets and three childrens tickets was 28 how much do the tickets cost?

Let's assume the cost of a child's ticket is x. Then, the cost of an adult's ticket would be 2x. The total cost of two adults' tickets and three children's tickets is 2(2x) + 3(x) = 4x + 3x = 7x. We know that 7x = 28, so x = 4. Therefore, the cost of a child's ticket is $4, and the cost of an adult's ticket is $8.


If an adult tickets costs 5.25 and a ticket for a child costs 2.25 how much does it cost for 2 adults and 2 children?

It costs 15.00 for two adults and two children.


Tickets are sold for 3.00 per child and 9.00 per adult they sold a total of 419. tickets for 1905.00 how many of each type of ticket did they sell?

Ok Let Children=C Let Adult=A Set up two equations: 3C+9A=$1905 C+A=419 tickets Solve the second equation for C or A, I'm choosing A A=419-C Sub it into the other equation 3C+9(419-C)=1905 3C+3771-9C=1905 Distribute 3771-6C=1905 Combine like terms -6C=(-1866) Subtract 3771 from both sides C=311 Divide by -6 Take 311 and plug it into the other equation "C+A=419" to find A=108 Answer Sold 108 adult tickets and 311 child tickets

Related questions

What are the prices at the empire cinema for tickets?

adult:£7.50 child:£5.00


The movie charges 4.00 for each child ticket and 7.00 for each adult ticket the Art Calub purchased a total of 20 tickets and spent 101.00 How many of each type of ticket did the club buy?

7 Adult tickets 13 Child tickets


A charity sells tickets for a fund raising dinner Each adult's ticket costs 10 and each child's ticket costs 5 A total of 1050 was raised by selling 130 tickets How many adult and child tickets?

10 adults & 10 children's


How much would it cost to get 1 day tickets for 7 adults and 3 kids to Disneyland?

1-Day Park Hopper$940 total ($97 each for adult tickets, $87 each for child tickets)1-Day 1-Park$690 total ($72 each for adult tickets, $62 each for child tickets)


How much are tickets at Regal Montrose Movies 12?

Adult tickets are $9.50 Senior tickets are $7.00 Child tickets are $7.50


A drama club sold 120 child tickets and 80 adult tickets to a play a child ticket is 3 dollars less than an adult ticket The club sold a total of 640 dollars worth of tickets What were the prices?

The tickets are $5 adult and $2 child. Here is the algebraic substitution. A = adult ticket money C = child ticket money 120C + 80A = 640 C = A-3 (three dollars less) 120 (A-3) + 80A = 640 120 A - 360 + 80A = 640 200 A = 1000 A = 5 C = A - 3 = 2 Checking your answer: 120(2) + 80 (5) = 240 + 400 = 640


How much are Bella terra movie tickets?

At Bella Terra there about $11.25 per adult and $8.25 per child


How much would 6 one day ticket for Walt Disney World cost?

One-day One-park$426.60 ($71.10 each) for 6 adult tickets$367.20 ($61.20 each) for 6 child ticketsOne-day Park Hopper$582.60 ($97.10 each) for 6 adult tickets$523.20 ($87.20 each) for 6 child tickets


At a basketball game adult tickets were sold at 7.50 each and student tickets at 3.50 each if 205 were sold and 1317.50 was collected how many tickets if each kind were sold?

The formula to determine the total money is nA + mC = 1317.50 where n is the number of adult tickets sold and A is the price of the adult tickets and m OS the number of child tickets and C is the price of a child ticket. Substituting in the actual prices we get... eq 1. n*7.50 + m * 3.50 = 1317.50 eq 2. n+m = 205 rearranging eq 2 we get n = 205 - m substituting this into eq 1 we get.. (205 -m) * 7.5 + m * 3.5 = 1317.50 Simplifying we get 1537.5 - 7.5m + 3.5m = 1317.50 1537.5 - 1317.5 = 4m 220 = 4m 55 = m substituting into eqn 2 we get n + 55 = 205 n = 150. Therefor 150 Adult tickets were sold 55 Child tickets were sold


At the movie theatre child admission is 5.40 and adult admission is 9.10 . On Friday 154 tickets were sold for a total sales of 1135.00 . How many child tickets were sold that day?

[100 + 54] 910 + 291.60 = 1,201.60 (too much) [90 + 64] 819 + 345.60 = 1,164.60 (too much) [80 + 74] 728 + 399.60 = 1,127.60 (too little) so answer is between 65 and 73 child tickets 1,135.00 - 1,127.60 = 7.40 9.10 - 5.40 = 3.70 7.40 / 3.70 = 2 so adjusting [80 + 74] by that 2 ... [82 + 72] 746.20 + 388.80 = 1,135.00 Answer: 72 child tickets (and 82 adult tickets)


How much do Adventure Island tickets cost?

For 1 park (Adventure Island) an adult ticket is $41.95 and for a child ticket it is $37.95, but if you want two parks (Adventure Island and Busch Gardens) it'll cost $89.95 for an adult and $79.95 for a child.


Sam took his family to the zoo an adults ticket is two times the cost of a child's ticket the total cost for two adults tickets and three childrens tickets was 28 how much do the tickets cost?

Let's assume the cost of a child's ticket is x. Then, the cost of an adult's ticket would be 2x. The total cost of two adults' tickets and three children's tickets is 2(2x) + 3(x) = 4x + 3x = 7x. We know that 7x = 28, so x = 4. Therefore, the cost of a child's ticket is $4, and the cost of an adult's ticket is $8.