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Tickets are sold for 3.00 per child and 9.00 per adult they sold a total of 419. tickets for 1905.00 how many of each type of ticket did they sell?
Wiki User
∙ 14y ago
Ok
Let Children=C
Let Adult=A
Set up two equations:
3C+9A=$1905
C+A=419 tickets
Solve the second equation for C or A, I'm choosing A
A=419-C
Sub it into the other equation
3C+9(419-C)=1905
3C+3771-9C=1905 Distribute
3771-6C=1905 Combine like terms
-6C=(-1866) Subtract 3771 from both sides
C=311 Divide by -6
Take 311 and plug it into the other equation "C+A=419"
to find A=108
Answer
Sold 108 adult tickets and 311 child tickets
Wiki User
∙ 14y ago
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Let A be the number of adult tickets sold. As 325 tickets in total were sold, the number sold to students was 325 - A. The income from the sale of adult tickets = A x 5 = 5A The income from the sale of student tickets = (325 - A) x 2 = 650 - 2A Total Income = 995 = 5A + 650 - 2A = 3A + 650 3A = 995 - 650 = 345 A = 115, therefore S = 325 - 115 = 210. 115 Adult tickets were sold and 210 Student tickets.
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answer is 325 adult tickets were sold ( fmtickets.com )
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A total of 725 tickets were sold for the school play There were 75 more student tickets sold than adult tickets How many adult tickets were sold?
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Michelle sold tickets for the basketball gameEach adult costs 3.00 and each student ticket cost 1.50 There were 105 tickets sold for a total of 250.00How many of each type of ticket were sold?
Sounds like a system of equations. X = adult ticket Y = student ticket Change all to pennies for convenience. X + Y = 105 300X + 150Y = 25000 -150(X + Y = 105) - 150X - 150Y = - 15750 300X + 150Y = 25000 -----------------------------------add them 150X = 9250 X = 62 adult tickets ------------------------ Y = 43 student tickets -------------------------- Those two prices added together = $250.50 So, we are a little off. I rounded the adult ticket number, but pieces of tickets can not be sold, so check work.
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The tickets are $5 adult and $2 child. Here is the algebraic substitution. A = adult ticket money C = child ticket money 120C + 80A = 640 C = A-3 (three dollars less) 120 (A-3) + 80A = 640 120 A - 360 + 80A = 640 200 A = 1000 A = 5 C = A - 3 = 2 Checking your answer: 120(2) + 80 (5) = 240 + 400 = 640
At a local theatre adult tickets cost 8 and student tickets cost 5 at a recent show 500 were sold for a total of 3475 how many adult tickets were sold?
answer is 325 adult tickets were sold ( fmtickets.com )
