length of diagonal of 20 of a 20 feet and 15 width.
length + width = 20/2 = 10 length = 7cm, width = 3cm
The length is 20 units and the width is 10 units
Length = 20 m and width = 9 m
Chile has a length of about 4300 km and a width of about 180 km, which means its length is about 24 times its width.
On any rectangular area: Area = (Length) x (Width) Length = (Area) / Width) Length = (800) / (20) = 40 feet
minimum width is like 10 cm and length is like 20 cm
The length and width are both 447.214 meters. (rounded)
If you're talking about a rectangle, then the answer is 100. There are 2 sides that have 40 as the length, and double that length is 80. There are 2 sides that have 10 as the width, and double that width is 20. 80 + 20 = 100.
The width is 2 !
Area is length times width: 140 square feet.
perimeter = 2 x (length + width) ⇒ length + width = perimeter ÷ 2 ⇒ length = (perimeter ÷ 2) - width So to find the length of the given rectangle, subtract the width from half the perimeter is how to do it. IF you meant "What is the length..." then: length = perimeter ÷ 2 - width = 40 ÷ 2 - 2 in = 20 - 2 in = 18 in