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If I understand your question exactly as it is phrased you are making two statements: 1)Width= X 2)Length= 4X So... Length= (Width times 4) Multiply the width by 4 and you have the length. Or in its simplest form: 4X
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The length of a rectangular poster is 7 in greater than the width the perimeter is 114 find the width and length?
Let the width be x and the length be x+7: 2(x+x+7) = 114 4x+14 = 114 4x = 114-14 4x = 100 x = 25 Therefore: width = 25 units and length = 32 units
The perimeter of a rectangle is 130m. The length of the rectangle is 25m more than the width. What are the lengths and widths of the rectangle?
x=width x+25=length 4x+50=130 4x=80 x=20 width is 20 length is 45
If the length of a rectangle is 3 meters more than the width and the perimeter of the rectangle is 48 meters?
width = x and length = x+3 the perimeter = x + x +( x+3) +(x + 3) = 48, solve for x 4x + 6 = 48m 4x = 42 x = 10.5m (width) x+3 = 13.5m (length)
5 The width of a rectangle is 15 feet less than its length and the perimeter is 210 feet Find the width?
If the width is x then the length is x+15 and the perimeter is x+x+x+15+x+15 (length + length + width + width). So: x + x + x + 15 + x + 15 = 210 4x + 30 = 210 {group x's} 4x = 180 {take 30 from each side} x = 45 {divide by 4} The width is 45 feet.
The length of a rectangle is four times its width. If the perimeter of the rectangle is 60 inches. What is the area of the rectangle?
Let the length be 4x and the width be x: 2(4x+x) = 60 8x+2x = 60 10x = 60 x = 6 So: length = 24 and width = 6 Area = length*width Area = 144 square inches
If the length of a rectangle is 4 more meters than the width and the perimeter is 40 meters what is the length?
Say x = the rectangle's width. Then: x + x + (x + 4) + (x + 4) = 40 4x + 8 = 40 4x = 32 x = 8 So, the width is 8. Therefore, the length is 4 more, or 12 meters.
A rectangle has width represented by x and length represented by 4x If the area of the rectangle is 80 find the value of x What is x?
length is 4x and width is x: 4x*x = 80 4x2 = 80 Divide both sides by 4: x2 = 20 Square root both sides: x = 4.472135955
The perimeter of a rectangle is 240 feet and Its length is 12 less than it's width what are the dimensions of the rectangle?
Let the length be x-12 and the width be x: 2(length+width) = perimeter 2(x-12+x) = 240 2x-24+2x = 240 4x = 240+24 4x = 264 x = 66 Therefore: length = 54 feet and width = 66 feet
The length of a rectangle is 4cm longer than the width if the perimeter of the rectangle is 20cms what is the area of the rectangle?
Let the length be x+4 and the width be x: 2(length+width) = perimeter 2(x+4+x) = 20 2x+8+2x = 20 4x = 20-8 4x = 12 x = 3 Therefore: length = 7 cm and the width = 3 cm Area = length*width = 7*3 = 21 square cm
The length of a rectangle is 5m greater than the width The perimeter is 150 m what is the width and length?
The Perimeter of a rectangle is 2(L+W). Let x represent the Width and x+5 represent the Length: 150 = 2(x+x+5) 150 = 2(2x+5) 150 = 4x+10 140 = 4x 35 = x The Width is 35m and the Length is 40m (35+5).
The length of a rectangle is 4cm longer than the width if the perimeter of the rectangle is 20cm what is the area of the rectangle?
First find the dimensions of the rectangle. Let the length be x+4 and the width be x: 2(x+4+x) = 20 2x+8+2x = 20 4x = 20-8 4x = 12 => x = 3 Therefore: length = 7cm and the width = 3cm Area = length*width => 21cm2
What is the formula for perimeter of a rectangle whose length is 5 more than its width?
Let the length be x+5 and the width be x:- Perimeter = 2*(x+5+x) or 4x+10
