If the width is x then the length is x+15 and the perimeter is x+x+x+15+x+15 (length + length + width + width). So:
x + x + x + 15 + x + 15 = 210
4x + 30 = 210 {group x's}
4x = 180 {take 30 from each side}
x = 45 {divide by 4}
The width is 45 feet.
Length = (Perimeter - twice width) / 2
The perimeter of a rectangle = 2 x (length + width) = 2 x (12 + 8) = 2 x 20 = 40 inches
Let the width of rectangle is w cm (Length is 12 cm more) so length is w + 12 Perimeter = 16 times of width 2 (length + width) = 16 * width Rest of the homework, do yourself.
64 meters
The perimeter of a rectangle is given by:P = 2l + 2w, where P is the perimeter of the rectangle, l is the length of the rectangle, and w is the width of the rectangle.P = 2(15) + 2(10) = 50 meters.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
you need length and width length multiply width = area length + length + width + width = perimeter
Length + length + width + width = perimeter. Length + width x 2 = perimeter
perimeter = 2 x (length + width) ⇒ length + width = perimeter ÷ 2 ⇒ length = (perimeter ÷ 2) - width So to find the length of the given rectangle, subtract the width from half the perimeter is how to do it. IF you meant "What is the length..." then: length = perimeter ÷ 2 - width = 40 ÷ 2 - 2 in = 20 - 2 in = 18 in
Perimeter = 2 * width + 2 * length, so rearranging --> width = (Perimeter / 2) - length
You divide the perimeter by the width and you get the lenght
Length = (Perimeter - twice width) / 2
length 18 width 7
by appying 2l+2w
Perimeter = 2*(L + W).