The result is all real numbers.
This is a question from a Florida Virtual School class, please call your teacher for help instead. Thank you.
Here are a few: 0 = 1 x = x + 1 (subtract "x" on each side, and you get the previous one!) x2 = -1 (if you want real numbers; however, it has two solutions in the complex numbers) ln x = -1 (same as above: no solution in the real numbers, but it has a solution in the complex numbers) ln x = 0 (no solution, neither in the real numbers, nor in the complex numbers) 0x = 5
DIVIDE BY ZERO ERROR Is an equation with no solution's answer. * * * * * It also depends on the domain of the variable(s). For example x + 3 = 2 has no solution if the domain for x is the counting numbers, Z. x*3 = 2 has no solution if the domain for x is the natural numbers, N. x2 = 2 has no solution if the domain for x is the rational numbers, Q. x2 = -2 has no solution if the domain for x is the real numbers, R.
The answer to the question depends on the set of numbers within which you are working. If you are working in integers, x2 = 2.25 has no solution. However, it does have a solution in rational numbers (x = 1.5). If working with rationals, x2 = 6 has no rational solution but it does have a solution in real numbers. Yet again, x2 = -6 has no solution in the reals, but does have a solution in complex numbers.
These numbers, such as pi, are known as trancendentalnumbers, because they represent a value that is not the solution of an algebraic equation or a quotient using real numbers.
The complex roots of an equation is any solution to that equation which cannot be expressed in terms of real numbers. For example, the equation 0 = x² + 5 does not have any solution in real numbers. But in complex numbers, it has solutions.
It is an equation which is insoluble in its domain. However, it may be soluble in a bigger domain.For example, x2 = 2 has no solution in the domain of rational numbers but it does in the real numbers, orx2 = -2 has no solution in the domain of real number but it does in imaginary numbers.
This is a question from a Florida Virtual School class, please call your teacher for help instead. Thank you.
When real numbers fail to provide a solution there is no real solution - its as simple as that! There is no integer solution for 2x = 3. To find a solution you need to extend the domain to rational numbers. There is no rational number solution to x^2 = 2, so you need to extend to the real numbers. For some equations that do not have a real solution, for example, x^2 + 1 = 0, there are solutions if the domain is extended to the complex field. x + 2 = x - 2 has no real solution nor a complex solution. However, it does have a solution in modulo 4 arithmetic. But in that case the original equation should have said so. When seeking a solution to an equation, it is customary to define the domain in which the answer (if any) may be found. - unless the context makes the domain clear.
Here are a few: 0 = 1 x = x + 1 (subtract "x" on each side, and you get the previous one!) x2 = -1 (if you want real numbers; however, it has two solutions in the complex numbers) ln x = -1 (same as above: no solution in the real numbers, but it has a solution in the complex numbers) ln x = 0 (no solution, neither in the real numbers, nor in the complex numbers) 0x = 5
DIVIDE BY ZERO ERROR Is an equation with no solution's answer. * * * * * It also depends on the domain of the variable(s). For example x + 3 = 2 has no solution if the domain for x is the counting numbers, Z. x*3 = 2 has no solution if the domain for x is the natural numbers, N. x2 = 2 has no solution if the domain for x is the rational numbers, Q. x2 = -2 has no solution if the domain for x is the real numbers, R.
The answer to the question depends on the set of numbers within which you are working. If you are working in integers, x2 = 2.25 has no solution. However, it does have a solution in rational numbers (x = 1.5). If working with rationals, x2 = 6 has no rational solution but it does have a solution in real numbers. Yet again, x2 = -6 has no solution in the reals, but does have a solution in complex numbers.
The equation has two real solutions.
These numbers, such as pi, are known as trancendentalnumbers, because they represent a value that is not the solution of an algebraic equation or a quotient using real numbers.
You solve the equation.
There is no simple way which can be easily applied to all forms of equations. If the variable(s) can be eliminated from the equation then, if what is left isfalse, then the equation has no solution.true, then the equation is an identity.The problem is complicated by the domains under consideration. The following are some examples of equations which have no solutions in one domain but do in another [larger] domain:x + 2 = 0 has no solution in N (natural numbers) but does in Z (integers)x*2 = 1 has no solution in Z but does in Q (rational numbers)X^2 = 2 has no solution in Q but does in R (real numbers)x^2 = - 2 has no solution in R but does in C (complex numbers).
Is it possible for a quadratic equation to have no real solution? please give an example and explain. Thank you