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We're not sure what the question means by "root". It may be what's usually
referred to as the "solution" of the equation ... the number that 'a' must be in
order to make the equation a true statement. Here's how to find the 'solution':
- 5a - 3 = 3a
Add 5a to each side:
- 3 = 8a
Divide each side by 8:
- 3/8 = a
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∙ 13y ago
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What is the value of a in 13a - 6 plus a equals 5a plus 3 plus 3a?
13a - 6 + a = 5a + 3 + 3a 13a + a - 5a - 3a = 3 + 6 6a = 9 6a/6 = 9/6 a = 3/2
What is the solutions when 9a2 equals 24a -16?
9a2=24a-16 9a2-24a+16=0 (3a-4)(3a-4)=0 3a-4=0 a=4/3 double root
What is 3a - 6 when a equals 3?
(3 x 3) - 6 = 3 3a-6=3 3a=3+6 3a=9 a=9/3 a=3
What is 3a equals 1?
3a = 1a = 1/3 (a third)
5a 7 equals -23 what equals a?
(5a).7 = -23 7(5a) = -23 35a = -23 a = -23/35 a= -0.657 (3 d.p.)
3a plus 5 equals 5a plus 3?
If 3a+5=5a+3, then: 3a+5 - 3a = 5a+3 - 3a 5=2a+3 5 - 3=2a+3 - 3 2=2a a=1
What is the answer to 5a plus 1 equals a-3?
Answer to: 5a + 1 = a - 3a = -1
What is the value of a in 13a - 6 plus a equals 5a plus 3 plus 3a?
13a - 6 + a = 5a + 3 + 3a 13a + a - 5a - 3a = 3 + 6 6a = 9 6a/6 = 9/6 a = 3/2
What is the answer to a plus b plus c equals 180 b equals 3a c equals 5a?
a + b + c = 180 b = 3a c = 5a Substituting the values of b and c into the first equation. a + 3a + 5a = 180 or 9a = 180 so that a = 20 then b = 3a = 3*20 = 60 and c = 5a = 5*20 = 100
What is -8a plus 3a?
-8a + 3a = (-8 + 3)a = (5)a = 5a
What 5a x 3a - 8a?
5a times 3a minus 8a = (5*3)*a2 - 8a = 15a2 - 8a
What is the solution of a 5a-5 equals 7 plus 2a?
5a - 5 = 7 + 2a ( subtract 2a from both sides) 3a - 5 = 7 (add 5 to both sides) 3a = 12 ( divide both sides by 3) a = 4
What is 3a x 2b x 5a simplified?
what is 5a x 3 x 2b
How do you factor 3a2-16a plus 5?
3a2 - 16a + 5 = 3a2 - 15a - a + 5 = 3a(a -5) - 1(a -5) = (3a - 1)(a - 5)
What is the solutions when 9a2 equals 24a -16?
9a2=24a-16 9a2-24a+16=0 (3a-4)(3a-4)=0 3a-4=0 a=4/3 double root
What is 3a - 6 when a equals 3?
(3 x 3) - 6 = 3 3a-6=3 3a=3+6 3a=9 a=9/3 a=3
Five times the first of three consecutive even integers is 14 more then 3 times the second?
Three consecutive even integers can be represented by a-2, a & a+2.Five times the first is 5a-10. Three times the second is 3a.5a-10 is 14 more than 3a, so 5a-10 = 3a+14Adding 10 to both sides: 5a = 3a+24Taking 3a from both sides: 2a = 24Therefore a=12The three consecutive even integers are 22, 24 and 26.
