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Five times the first of three consecutive even integers is 14 more then 3 times the second?
Updated: 8/17/2019
Wiki User
∙ 14y agoBest Answer
- Three consecutive even integers can be represented by a-2, a & a+2.
- Five times the first is 5a-10. Three times the second is 3a.
- 5a-10 is 14 more than 3a, so 5a-10 = 3a+14
- Adding 10 to both sides: 5a = 3a+24
- Taking 3a from both sides: 2a = 24
- Therefore a=12
The three consecutive even integers are 22, 24 and 26.
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∙ 14y agoThis answer is:
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