There are infinitely many rules. SOme of these are:
y = x/80
y = 80/x
y = x + 79
y = 81 - x
y = sqrt(x+1) - 8
y = 1/2 x + 1
y = x(x + 1)
There is no specific rule. y = -sqrt(x) y = x - 12 y = -x/3 y = x2 - 84 are all possible.
The graph of y = x + 1 is a straight line with slope 1 which passes through the point (0, 1) If you have y < x + 1, then it is the area under the line y = x + 1 and is shown by shading the area under the line. If you have y > x + 1, then it is the area above the line y = x + 1 and is shown by shading the area above the line.
y=m(x)+b
y = x/3
-81
y = 1/2 x + 1
There is no specific rule. Among the infinitely many possibilities are y = 5 (whatever x is) y = x + 4 y = 27x - 22 y = x2 + 4x y = 28x/4 - 2
y = x(x + 1)
(x' , y') = (-x + 1 , y + 4)
There is no specific rule. y = -sqrt(x) y = x - 12 y = -x/3 y = x2 - 84 are all possible.
That's the function rule.
The rule for a set of ordered pairs is the statement that states the relationship of of a certain value to another value.For example:given the set of ordered pair { (1,2) , (3,4) , (5,6) , (7,8) }we notice that the value of y is increased by 1 as the value of x varies.For instance, in the first ordered pair which is (1,2) where 1 is x and 2 is y such that (x,y), 1 increased by 1. In other words, x is increased by 1.So we say that the rule of the ordered pair is:{(x,y) | y = x + 1 }read as "The set of ordered pairs such that y is equal to x plus one"
The graph of y = x + 1 is a straight line with slope 1 which passes through the point (0, 1) If you have y < x + 1, then it is the area under the line y = x + 1 and is shown by shading the area under the line. If you have y > x + 1, then it is the area above the line y = x + 1 and is shown by shading the area above the line.
Let's denote the two square numbers as x^2 and y^2. The difference between two square numbers can be expressed as (x^2 - y^2), which can be factored into (x + y)(x - y). Since the difference is 80, we have (x + y)(x - y) = 80. The factors of 80 are 1, 2, 4, 5, 8, 10, 16, 20, 40, and 80. By testing out different combinations of these factors, we find that the pair of square numbers that make a difference of 80 is 82^2 and 2^2.
y=m(x)+b