x^3+y^3 Cube root of the first, x plus cube root of the last, y times What it takes to make the first number, x^2 Opposite sign, - Product of the two cube roots, -xy Then what it takes to make the last. (x+y)(X^2-xy+y^2)
7
Derivative of sin x = cos x, so chain rule to derive 8x = 8 , answer is 8cos8x
y = 6 - 4 = 2, thus 3y = 3 x 2 = 6
Assuming that the equation is y = 3x + 2, y decreases by three times as much as the decrease in x.
3x-y to the third becomes (x+x)+x-y*y*y the question is (3x-y)3
There is no specific rule. y = -sqrt(x) y = x - 12 y = -x/3 y = x2 - 84 are all possible.
y=m(x)+b
(x,y) --> (x,-y)
(x,y)-> (-y,x)
2 x 3 x 3 x y x y x y
(x=y) (y=-x)
There is no specific rule. Among the infinitely many possibilities are y = 5 (whatever x is) y = x + 4 y = 27x - 22 y = x2 + 4x y = 28x/4 - 2
There are infinitely many rules. SOme of these are: y = x/80 y = 80/x y = x + 79 y = 81 - x y = sqrt(x+1) - 8
f(x, y) = (x, -y)
If X and Y are the first two numbers, then the third must be = 67 - (X+Y)
Y is the output of x, which is the input. So y= x + 2, y is the result of x + 2. Y is the dependent variable, and x is the independent constant.