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A = arcsin 12
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If θ is an acute angle and sin θ equals 12 then cos θ equals?
The value of sine and cosine varies between -1 and 1, it never can be 12. If you mean .12, then we have: sin x = .12 x = sin-1 .12 x = 6.89 degrees So that, cos x = cos 6.89 = .99
Solve the right triangle with A equals 52 degrees 15' and a equals 6.7808?
Angle A = 52° 15' = 52 25° therefore angle B = 90 - 52.25 = 37.75°. Using the Sine Rule : a/sin A = b/sin B. 6.7808/sin 52.25 = b/sin 37.75 : b = 6.7808 sin 37.75 ÷ sin 52.25 = 5.2503 Either using the Sine Rule or Pythagoras gives the length of the hypotenuse as 8.5758
How sin90degree equals 1?
Sin = Opposite/ Hypotenuse. If the angle is 90o then the Opposite IS the Hypotenuse so the ratio is 1.
How sin90 equals 1?
Because sin = opp/hyp and the opposite side to a 90 degree angle is the hypotenuse.
True or false in triangle ABC with the right agnel at C if B equals 13.5 and C equals 28.9 then angle B equals 27.8?
True : Sin B = 13.5/28.9 = 0.46713 : Therefore Angle B = 27.8 (1dp)
Tan equals 0.3421 sin equals 3237 Which quadrant does it terminate?
Assuming sin equals 0.3237, the angle is in quadrant I.
If θ is an acute angle and sin θ equals 12 then cos θ equals?
The value of sine and cosine varies between -1 and 1, it never can be 12. If you mean .12, then we have: sin x = .12 x = sin-1 .12 x = 6.89 degrees So that, cos x = cos 6.89 = .99
What is the sin of angle A 5 13 12?
The dimensions given fits that of a right angle triangle and sin^-1(12/13) = 67.38 degrees
If θ is an acute angle and sin θ equals 2 then cos θ?
it equals 4
In triangle abc given that angle a equals 57 angle b equals 73 and ab equals 24cm find the length of ac?
The sum of the angles inside a triangle is equal to 180°. We are told that angle a is 57°, and that angle b is 73°. This tells us that angle c is is (180 - 57 - 73)°, or 50°. We are also given the length of side ab, 25cm. With that, we can use the sine rule to calculate the length of side ac: sin(b) / |ac| = sin(c) / |ab| ∴ sin(73°) / |ac| = sin(50°) / 24cm ∴ |ac| = 24cm · sin(73°) / sin(50°) ∴ |ac| ≈ 29.96cm
Sine of 10 degrees x 12 equals?
Sin(10)*12 = 12*sin(10) = 12*0.1736 = 2.0838, approx.
Solve the right triangle with A equals 52 degrees 15' and a equals 6.7808?
Angle A = 52° 15' = 52 25° therefore angle B = 90 - 52.25 = 37.75°. Using the Sine Rule : a/sin A = b/sin B. 6.7808/sin 52.25 = b/sin 37.75 : b = 6.7808 sin 37.75 ÷ sin 52.25 = 5.2503 Either using the Sine Rule or Pythagoras gives the length of the hypotenuse as 8.5758
How sin90degree equals 1?
Sin = Opposite/ Hypotenuse. If the angle is 90o then the Opposite IS the Hypotenuse so the ratio is 1.
How sin90 equals 1?
Because sin = opp/hyp and the opposite side to a 90 degree angle is the hypotenuse.
True or false in triangle ABC with the right agnel at C if B equals 13.5 and C equals 28.9 then angle B equals 27.8?
True : Sin B = 13.5/28.9 = 0.46713 : Therefore Angle B = 27.8 (1dp)
The refractive index of water is 1.33 a ray is incident from water on air at an angle of incidence equal to 30 degree what is the angle of refraction in air?
nwater * sin 30=nair *sin(angle of refraction) 1.33*0.5=1*sin(angle of refraction) sin(angle of refractiob)=0.665 angle of refraction inair=41.6 degrees nwater * sin 30=nair *sin(angle of refraction) 1.33*0.5=1*sin(angle of refraction) sin(angle of refractiob)=0.665 angle of refraction inair=41.6 degrees
If the area of triangle ABC is 27cm2 BC is 12cm and angle BCA is 98 degrees what is length AC?
Area = 1/2*a*b*sin(C) where a = BC, b = AC and angle C = angle BCA 27 = 0.5*12*AC*sin(98) So AC = 27/[0.5*12*sin(98)] = 4.54 approx.
