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This is a classic Pythagorean triangle.

Although you have given the side lengths, you have NOT given a letter to correspond , with the given side.

However,

Let 12 be the adjacentr side (base)

Let '5' be the opposite side ( perpendicular )

Let '13' by the hypotenuse.

Sin(Angle) = opposite / hypotenuse = 5/13

Angle = Sin^(-1) 5/13 = 22.619... degrees. NB This is the angle between the hypotenuse and the base(adjacent)

Now 'swopping' things around , we take the angle between the hypotenuse and the perpendicular (opposite) . This now becomes perpendicular(adjacent) and the base becomes the opposite.

Hence

Sin(angle) = 12/13

Angle = Sin^(-1) 12/13 = 67.380.... degrees. The angle at the 'top' of the triangle.

Verification. ' 90 + 67.380... + 22.619... = 180 ( allow for calculator decimals).

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lenpollock

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1y ago

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What is the cos of angle 'a' with the measurements 5 13 12?

Use Cosine Rule a^(2) = b^(2) + c^(2) - 2bcCosA Algebrically rearrange CosA = [a^(2) - b^(2) - c^(2)] / -2bc Substitute CosA = [13^(2) - 12^(2) - 5^(2)# / -2(12)(5) CosA = [ 169 - 144 - 25] / -120 Cos)A) = [0] / -120 CosA = 0 A = 90 degrees (the right angle opposite the hypotenuse)/ However, If 'A' is the angle between '12' & '13' then 'a' is the side '5' Hence (Notice the rearrangement of the numerical values). CosA = [5^(2) - 12^(2) - 13^(2) ] / -2(12)(13) CosA = [ 25 - 144 -169] / -312 CosA = [ -288[/-312 CosA = 288/312 A = Cos^(-1) [288/312] A = 22.61986495.... degrees.


What is the tan of angle B in a 12 by 13 by 5 triangle?

In a triangle with sides measuring 12, 13, and 5, we can identify the angle opposite the side measuring 5 as angle B. To find the tangent of angle B, we use the formula ( \tan(B) = \frac{\text{opposite}}{\text{adjacent}} ). Here, the side opposite angle B is 5, and the adjacent side (which can be either of the other two sides depending on which angle we consider) is 12. Therefore, ( \tan(B) = \frac{5}{12} ).


What is the cos of angle B 5 13 12?

To find the cosine of angle B given the sides of a triangle, you typically use the cosine rule or the relationship between the sides. However, the values "5," "13," and "12" seem to refer to the lengths of the sides of a triangle. If these correspond to a triangle with sides a = 5, b = 12, and c = 13, you can use the cosine rule: ( \cos(B) = \frac{a^2 + c^2 - b^2}{2ac} ). Plugging in the values, ( \cos(B) = \frac{5^2 + 13^2 - 12^2}{2 \cdot 5 \cdot 13} = \frac{25 + 169 - 144}{130} = \frac{50}{130} ), which simplifies to ( \cos(B) = \frac{5}{13} ).


What is sin M written as a simplified fraction?

Sin(M) = 15/39 Simplified Sin(M) = 5/13 44Because '3' is a common factor to both '15' ( 5 x 3) & 39' ( 13 x 3) . So cancel down (reduce/simplify) by '3'.


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SOHCAHTOAThis would be the sine, the opposite over the hypotenuse.5000/h=sin 30 degrees5000 divided by sin 30 degrees= trail

Related Questions

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Wide Angles was created on 2003-09-09.