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If θ is an acute angle and sin θ equals 12 then cos θ equals?
The value of sine and cosine varies between -1 and 1, it never can be 12. If you mean .12, then we have: sin x = .12 x = sin-1 .12 x = 6.89 degrees So that, cos x = cos 6.89 = .99
The tanget of an angle equals the ratio of the?
Tan(ANGLE) = Sin(ANGLE) / Cos(ANGLE).
Solve the right triangle with A equals 52 degrees 15' and a equals 6.7808?
Angle A = 52° 15' = 52 25° therefore angle B = 90 - 52.25 = 37.75°. Using the Sine Rule : a/sin A = b/sin B. 6.7808/sin 52.25 = b/sin 37.75 : b = 6.7808 sin 37.75 ÷ sin 52.25 = 5.2503 Either using the Sine Rule or Pythagoras gives the length of the hypotenuse as 8.5758
How sin90degree equals 1?
Sin = Opposite/ Hypotenuse. If the angle is 90o then the Opposite IS the Hypotenuse so the ratio is 1.
How sin90 equals 1?
Because sin = opp/hyp and the opposite side to a 90 degree angle is the hypotenuse.
If θ is an acute angle and sin θ equals 12 then cos θ equals?
The value of sine and cosine varies between -1 and 1, it never can be 12. If you mean .12, then we have: sin x = .12 x = sin-1 .12 x = 6.89 degrees So that, cos x = cos 6.89 = .99
Tan equals 0.3421 sin equals 3237 Which quadrant does it terminate?
Assuming sin equals 0.3237, the angle is in quadrant I.
The tanget of an angle equals the ratio of the?
Tan(ANGLE) = Sin(ANGLE) / Cos(ANGLE).
If θ is an acute angle and sin θ equals 2 then cos θ?
it equals 4
What is the sin of angle A 5 13 12?
The dimensions given fits that of a right angle triangle and sin^-1(12/13) = 67.38 degrees
In triangle abc given that angle a equals 57 angle b equals 73 and ab equals 24cm find the length of ac?
The sum of the angles inside a triangle is equal to 180°. We are told that angle a is 57°, and that angle b is 73°. This tells us that angle c is is (180 - 57 - 73)°, or 50°. We are also given the length of side ab, 25cm. With that, we can use the sine rule to calculate the length of side ac: sin(b) / |ac| = sin(c) / |ab| ∴ sin(73°) / |ac| = sin(50°) / 24cm ∴ |ac| = 24cm · sin(73°) / sin(50°) ∴ |ac| ≈ 29.96cm
Sine of 10 degrees x 12 equals?
Sin(10)*12 = 12*sin(10) = 12*0.1736 = 2.0838, approx.
Solve the right triangle with A equals 52 degrees 15' and a equals 6.7808?
Angle A = 52° 15' = 52 25° therefore angle B = 90 - 52.25 = 37.75°. Using the Sine Rule : a/sin A = b/sin B. 6.7808/sin 52.25 = b/sin 37.75 : b = 6.7808 sin 37.75 ÷ sin 52.25 = 5.2503 Either using the Sine Rule or Pythagoras gives the length of the hypotenuse as 8.5758
How sin90degree equals 1?
Sin = Opposite/ Hypotenuse. If the angle is 90o then the Opposite IS the Hypotenuse so the ratio is 1.
How sin90 equals 1?
Because sin = opp/hyp and the opposite side to a 90 degree angle is the hypotenuse.
True or false in triangle ABC with the right agnel at C if B equals 13.5 and C equals 28.9 then angle B equals 27.8?
True : Sin B = 13.5/28.9 = 0.46713 : Therefore Angle B = 27.8 (1dp)
What is the sin of angle B if the angles are 5 12 and 13?
This is a classic Pythagorean triangle. Although you have given the side lengths, you have NOT given a letter to correspond , with the given side. However, Let 12 be the adjacentr side (base) Let '5' be the opposite side ( perpendicular ) Let '13' by the hypotenuse. Sin(Angle) = opposite / hypotenuse = 5/13 Angle = Sin^(-1) 5/13 = 22.619... degrees. NB This is the angle between the hypotenuse and the base(adjacent) Now 'swopping' things around , we take the angle between the hypotenuse and the perpendicular (opposite) . This now becomes perpendicular(adjacent) and the base becomes the opposite. Hence Sin(angle) = 12/13 Angle = Sin^(-1) 12/13 = 67.380.... degrees. The angle at the 'top' of the triangle. Verification. ' 90 + 67.380... + 22.619... = 180 ( allow for calculator decimals).
