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If θ is an acute angle and sin θ equals 12 then cos θ equals?
The value of sine and cosine varies between -1 and 1, it never can be 12. If you mean .12, then we have: sin x = .12 x = sin-1 .12 x = 6.89 degrees So that, cos x = cos 6.89 = .99
Solve the right triangle with A equals 52 degrees 15' and a equals 6.7808?
Angle A = 52° 15' = 52 25° therefore angle B = 90 - 52.25 = 37.75°. Using the Sine Rule : a/sin A = b/sin B. 6.7808/sin 52.25 = b/sin 37.75 : b = 6.7808 sin 37.75 ÷ sin 52.25 = 5.2503 Either using the Sine Rule or Pythagoras gives the length of the hypotenuse as 8.5758
How sin90degree equals 1?
Sin = Opposite/ Hypotenuse. If the angle is 90o then the Opposite IS the Hypotenuse so the ratio is 1.
How sin90 equals 1?
Because sin = opp/hyp and the opposite side to a 90 degree angle is the hypotenuse.
True or false in triangle ABC with the right agnel at C if B equals 13.5 and C equals 28.9 then angle B equals 27.8?
True : Sin B = 13.5/28.9 = 0.46713 : Therefore Angle B = 27.8 (1dp)
