3.5
y = 2x + 1.
If you mean x intercept -2 and y intercept -1 then the points are (-2, 0 and (0,-1) Slope: -1/2 Equation: y - -1 = -1/2(x -0) => 2y --2 = -x +0 => 2y = -x -2 Equation in slope intercept form: y = -1/2x -1
5
7
y = x/4 - 1
That's not an equation. It doesn't have a graph or an intercept.
The graph of an equation can have a slope and an intercept. Sadly, "x-y-1" is not an equation, so it doesn't have any.
To find the equation of a line with an x-intercept of 4 and a y-intercept of -2, we can use the intercept form of the equation of a line, which is ( \frac{x}{a} + \frac{y}{b} = 1 ), where ( a ) is the x-intercept and ( b ) is the y-intercept. Substituting the values, we get ( \frac{x}{4} + \frac{y}{-2} = 1 ). Multiplying through by -4 to eliminate the fractions, the equation simplifies to ( 2x + 4y = -8 ) or, rearranging, ( y = -\frac{1}{2}x - 2 ).
The equation of a line in slope-intercept form is given by ( y = mx + b ), where ( m ) is the slope and ( b ) is the y-intercept. Given a slope of ( \frac{4}{5} ) and a y-intercept of -1, the equation of the line is ( y = \frac{4}{5}x - 1 ).
y = mx + b <-- (Slope Intercept equation) y = 4x - 1 <-- (Slope Intercept form)
1
If you mean: y = 11x+1 then the y intercept is 1 and the slope is 11