Unfortunately WikiAnswers, at the time of writing, has a problem formatting mathematical symbols such as "=" and "+" in the question, so as Supervisor I've altered the wording. I'm assuming that you're asking for the slope and y-intercept of the straight line:
y=18x+12
The slope is always the co-efficient of x, in this case 18
The y-intercept is determined by setting x to zero, so
y-int=0x+12 = 12
y=-18x+17. Since this is already in Slope-Intercept form, we can determine that the slope is negative 18.
to get slope equation needs to be in standard form y = mx + b where m = slope and b = y intercept (value at x = 0) 18 x + 3y = 30 3y = -18x +30 y = -6x +10 m = slope = -6
The discriminant is 0.
(2x4) + (8x3) + 18x 8 + 24 + 18x 32 + 18x
11x = 20x +1811x-20x=18x(11-20)=18-9x=18x=-2
If you mean: y = -18x+17 then the slope is -18 and the y intercept is 17
2x2+18x = 20 2x2+18x-20 = 0 x2+9x-10 = 0 (x+10)(x-1) = 0 x = -10 or x = 1
It has one double solution.
10x + 17 = 4x - 16x = -18x = -3
18x + 12y = 72 to get x-int. put y=0 18x + (12)(0) = 72 18x = 72 x = 4 your x-intercept is 4. this is the place where the line goes through the x-axis.
18x= 19818x/18 = 198/18x = 11
-5 + 12x = 18x + 7Subtract 7 from each side:-12 + 12x = 18xSubtract 12x from each side:-12 = 6xDivide each side by 6:-2 = x