If you mean: y = -2x+17 then the perpendicular slope line is 1/2 or 0.5
It will have the same slope but a different y intercept
Points: (-12, -17) and (21, 5) Slope: 2/3
y=-18x+17. Since this is already in Slope-Intercept form, we can determine that the slope is negative 18.
17
If you mean: y - 5 = -3(x - 17) then:The slope is -3 and the line passes through the point (17, 5).It can be rearranged into y = -3x + 56 to also give the slope of -3 and the y-intercept of 56
write an equation that has a slope 7 and passes through the point (2,17)
If you mean: y+3 = -4(x-5) then y = -4x+17 whereas the slope of the line is -4 and the y intercept is 17
First find the slope of the given line . 5x + 8y =17 Put this into the 'y = mx + c '. form. Hence 8y = -5x + 17 y =(-5/8)x +17/8 '-5/8' is the slope of the given line. To find the perpendicular slope use the equation mm' = -1 Hence substituting (-5/8)m' = -1 m' = (-1)(-8/5) (Note the inversion of the numbers) m' = 8/5 (Note the double negative multiplies out to a positive), = 1 3/5 = 1.6 is the slope of the perpendicular line.
17/12
Slope = (difference in y coordinate) / (difference in x coordinate) = (17 - 5) / (4 - 2) = 12/2 = 6
A line with slope of zero is horizontal. A line with no slope is vertical because slope is undefined on a vertical line.