18x +12y = 0
y=-18x+17. Since this is already in Slope-Intercept form, we can determine that the slope is negative 18.
The discriminant is 0.
(2x4) + (8x3) + 18x 8 + 24 + 18x 32 + 18x
to get slope equation needs to be in standard form y = mx + b where m = slope and b = y intercept (value at x = 0) 18 x + 3y = 30 3y = -18x +30 y = -6x +10 m = slope = -6
18x +12y = 0
y=-18x+17. Since this is already in Slope-Intercept form, we can determine that the slope is negative 18.
15x+12y+22+3w-2y+3x+14-12+3w original = 15x+3x+12y-2y+3w+3w+22+14-12 group = 18x+10y+6w+24 answer
The discriminant is 0.
Unfortunately WikiAnswers, at the time of writing, has a problem formatting mathematical symbols such as "=" and "+" in the question, so as Supervisor I've altered the wording. I'm assuming that you're asking for the slope and y-intercept of the straight line:y=18x+12The slope is always the co-efficient of x, in this case 18The y-intercept is determined by setting x to zero, soy-int=0x+12 = 12
(2x4) + (8x3) + 18x 8 + 24 + 18x 32 + 18x
to get slope equation needs to be in standard form y = mx + b where m = slope and b = y intercept (value at x = 0) 18 x + 3y = 30 3y = -18x +30 y = -6x +10 m = slope = -6
11x = 20x +1811x-20x=18x(11-20)=18-9x=18x=-2
If you mean: y = -18x+17 then the slope is -18 and the y intercept is 17
18x - 9y + 3z = 18First, just to clean it up a bit, divide both sides of the equation by 3.(This doesn't change the equation or its graph in any way.)6x - 3y + z = 6At the 'x'-intercept, 'y' and 'z' are zero:6x = 6x = 1At the 'y'-intercept, 'x' and 'z' are zero:-3y = 6-y = 2y = -2At the 'z'-intercept, 'x' and 'y' are zero:z = 6
2x2+18x = 20 2x2+18x-20 = 0 x2+9x-10 = 0 (x+10)(x-1) = 0 x = -10 or x = 1
It has one double solution.