Points: (1, 1) and (5, -1)
Slope: -1/2
Wiki User
∙ 7y agoThe slope of the line passing through any two points with coordinates x,y and x',y' is (y' - y)/(x' - x). In this instance, the slope is (5 - 4)/(0 - 2) = -1/2 .
Points: (2, 5) and (-4, 1) Slope: 2/3 Equation: 3y = 2x+11
It will have the same slope but with a different y intercept.
-24
Slope: 2/3 Point: (9, 11) Equation: 3y = 2x+15
Finding the slope for the line passing through these two points (-6,7) and (0,4) deltax = 6 deltay = -11 the slope = deltay/deltax = -11/6 or -1.83333333..... or angel = -613895 dg I hope this answers your question!
The slope of the line passing through any two points with coordinates x,y and x',y' is (y' - y)/(x' - x). In this instance, the slope is (5 - 4)/(0 - 2) = -1/2 .
Points: (2, 5) and (-4, 1) Slope: 2/3 Equation: 3y = 2x+11
Use the point slope form. Y - Y1 = m(X - X1) Y - 11 = -3[X - (-3)] Y - 11 = -3X + 9 Y = -3X + 20
If you mean: (2, 13) and (-4, -11) then the slope is 4 and both equations will have the same slope of 4 but with different y intercepts
Slope of line through (3,5) and (0,11) = (change in y coordinate)/(change in x coordinate) = (5 - 11)/(3 - 0) = -6/3 = -2
It will have the same slope but with a different y intercept.
-24
Slope: 2/3 Point: (9, 11) Equation: 3y = 2x+15
If you mean points of: (1, 1) and (4, -1) Then the slope works out as: -2/3
It is: y = 2x+11
To find the slope of a perpendicular line, take the negative reciprocal of the slope of the given line. (Flip the top and bottom of the fraction and change the sign.) The slope of a line that is perpendicular to a line with a slope of -2/3 is 3/2, (or 11/2 or 1.5).