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Points: (1, 1) and (5, -1)

Slope: -1/2

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Q: What is the slope of a line passing through (11) and (5-1)?

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The slope of the line passing through any two points with coordinates x,y and x',y' is (y' - y)/(x' - x). In this instance, the slope is (5 - 4)/(0 - 2) = -1/2 .

Points: (2, 5) and (-4, 1) Slope: 2/3 Equation: 3y = 2x+11

It will have the same slope but with a different y intercept.

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Slope: 2/3 Point: (9, 11) Equation: 3y = 2x+15

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Finding the slope for the line passing through these two points (-6,7) and (0,4) deltax = 6 deltay = -11 the slope = deltay/deltax = -11/6 or -1.83333333..... or angel = -613895 dg I hope this answers your question!

The slope of the line passing through any two points with coordinates x,y and x',y' is (y' - y)/(x' - x). In this instance, the slope is (5 - 4)/(0 - 2) = -1/2 .

Points: (2, 5) and (-4, 1) Slope: 2/3 Equation: 3y = 2x+11

Use the point slope form. Y - Y1 = m(X - X1) Y - 11 = -3[X - (-3)] Y - 11 = -3X + 9 Y = -3X + 20

If you mean: (2, 13) and (-4, -11) then the slope is 4 and both equations will have the same slope of 4 but with different y intercepts

Slope of line through (3,5) and (0,11) = (change in y coordinate)/(change in x coordinate) = (5 - 11)/(3 - 0) = -6/3 = -2

It will have the same slope but with a different y intercept.

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Slope: 2/3 Point: (9, 11) Equation: 3y = 2x+15

If you mean points of: (1, 1) and (4, -1) Then the slope works out as: -2/3

It is: y = 2x+11

To find the slope of a perpendicular line, take the negative reciprocal of the slope of the given line. (Flip the top and bottom of the fraction and change the sign.) The slope of a line that is perpendicular to a line with a slope of -2/3 is 3/2, (or 11/2 or 1.5).