0
To find the slope use the equation
m = (y(1) - y(2)) / (x(1) - x(2))
So forthe points (1,1) & ( 5, -1)
We have
m = (1 - - 1) / (1 - 5)
m = 2 / -4
m = 1/-2
m = -1/2 or -0.5 is the slope .
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Find the slope of the line passing through the points 2 5 and 0 4?
The slope of the line passing through any two points with coordinates x,y and x',y' is (y' - y)/(x' - x). In this instance, the slope is (5 - 4)/(0 - 2) = -1/2 .
What is an equation of a line passing through (25) and (-41)?
Points: (2, 5) and (-4, 1) Slope: 2/3 Equation: 3y = 2x+11
What is the slope of a line perpendicular to a line with a slope of -11 divided by 13?
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What is the ecuation of the line that has a slope of 2 3 and passes through 9 11?
Slope: 2/3 Point: (9, 11) Equation: 3y = 2x+15
What is the slope of the line through (11)and (4-1)?
If you mean points of: (1, 1) and (4, -1) Then the slope works out as: -2/3
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