To find the slope use the equation
m = (y(1) - y(2)) / (x(1) - x(2))
So forthe points (1,1) & ( 5, -1)
We have
m = (1 - - 1) / (1 - 5)
m = 2 / -4
m = 1/-2
m = -1/2 or -0.5 is the slope .
Points: (1, 1) and (5, -1)
Slope: -1/2
The slope of the line passing through any two points with coordinates x,y and x',y' is (y' - y)/(x' - x). In this instance, the slope is (5 - 4)/(0 - 2) = -1/2 .
Points: (2, 5) and (-4, 1) Slope: 2/3 Equation: 3y = 2x+11
Slope: 2/3 Point: (9, 11) Equation: 3y = 2x+15
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If you mean points of: (1, 1) and (4, -1) Then the slope works out as: -2/3
Finding the slope for the line passing through these two points (-6,7) and (0,4) deltax = 6 deltay = -11 the slope = deltay/deltax = -11/6 or -1.83333333..... or angel = -613895 dg I hope this answers your question!
The slope of the line passing through any two points with coordinates x,y and x',y' is (y' - y)/(x' - x). In this instance, the slope is (5 - 4)/(0 - 2) = -1/2 .
Points: (2, 5) and (-4, 1) Slope: 2/3 Equation: 3y = 2x+11
Use the point slope form. Y - Y1 = m(X - X1) Y - 11 = -3[X - (-3)] Y - 11 = -3X + 9 Y = -3X + 20
If you mean: (2, 13) and (-4, -11) then the slope is 4 and both equations will have the same slope of 4 but with different y intercepts
Slope of line through (3,5) and (0,11) = (change in y coordinate)/(change in x coordinate) = (5 - 11)/(3 - 0) = -6/3 = -2
Slope: 2/3 Point: (9, 11) Equation: 3y = 2x+15
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If you mean points of: (1, 1) and (4, -1) Then the slope works out as: -2/3
It is: y = 2x+11
If you mean y = 11x then the slope is 11
Points don't have slope. In fact, they don't have anything, except location. If you want to use a couple of points to build something that has slope, one thing you could do might be to draw a line that goes through them. If you draw a line through these two points, the line has slope of negative 11/7. But the points still don't have anything except a couple of locations.