The slope of the line passing through any two points with coordinates x,y and x',y' is (y' - y)/(x' - x). In this instance, the slope is (5 - 4)/(0 - 2) = -1/2 .
Points: (2, 5) and (-4, 1) Slope: 2/3 Equation: 3y = 2x+11
Slope: 2/3 Point: (9, 11) Equation: 3y = 2x+15
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If you mean points of: (1, 1) and (4, -1) Then the slope works out as: -2/3
The slope of a line passing through two points (x1, y1) and (x2, y2) is given by the formula: (y2 - y1) / (x2 - x1). Using the points (0, -4) and (-6, 7), the slope is: (7 - (-4)) / (-6 - 0) = 11 / -6 = -11/6.
The slope of the line passing through any two points with coordinates x,y and x',y' is (y' - y)/(x' - x). In this instance, the slope is (5 - 4)/(0 - 2) = -1/2 .
Points: (2, 5) and (-4, 1) Slope: 2/3 Equation: 3y = 2x+11
Use the point slope form. Y - Y1 = m(X - X1) Y - 11 = -3[X - (-3)] Y - 11 = -3X + 9 Y = -3X + 20
If you mean: (2, 13) and (-4, -11) then the slope is 4 and both equations will have the same slope of 4 but with different y intercepts
Slope of line through (3,5) and (0,11) = (change in y coordinate)/(change in x coordinate) = (5 - 11)/(3 - 0) = -6/3 = -2
Slope: 2/3 Point: (9, 11) Equation: 3y = 2x+15
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If you mean points of: (1, 1) and (4, -1) Then the slope works out as: -2/3
It is: y = 2x+11
If you mean y = 11x then the slope is 11
Points don't have slope. In fact, they don't have anything, except location. If you want to use a couple of points to build something that has slope, one thing you could do might be to draw a line that goes through them. If you draw a line through these two points, the line has slope of negative 11/7. But the points still don't have anything except a couple of locations.