Slope of line through (3,5) and (0,11)
= (change in y coordinate)/(change in x coordinate) = (5 - 11)/(3 - 0) = -6/3 = -2
If you mean: (2, 13) and (-4, -11) then the slope is 4 and both equations will have the same slope of 4 but with different y intercepts
Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.
Points: (1, 11) and (-2, 2) Slope: (11-2)/(1--2) = 3 Equation: y-11 = 3(x-1) => y = 3x+8 Equation: y-2 = 3(x--2) => y = 3x+8
m = - 5 (-4,9) Point slope form. Y - Y1 = m(X - X1) Y - 9 = - 5{X - (-4)} Y - 9 = -5(X + 4) Y - 9 = -5X - 20 y = -5X - 11 ----------------
We want a line that passes through the points (22,0) and (-2,3)The general formula for a line is y = mx +bWhere M is our slope, and B is the y-intercept.We don't know either, so we have to use the points given to figure out 1) the slope 2) the y intercept.You can find slope by using the slope formuladifference in y's divided by the difference in x's(22,0) is (x,y) and (-2,3) is also (x,y)(0 - 3)/(22 - (-2))-3/24 = -1/8Our slope is -1/8.Now we plug m = -1/8 into the general formula y = mx +b.We also pick ONE set of points, and plug that in for x and y. (it's easier to pick smaller numbers)y = mx + b3 = (-1/8)(-2) + bNow we solve for b.3 = 1/4 + b3 - 1/4 = b12/4 - 1/4 = b (I changed 3 to a fraction to work with -1/4)11/4 = b(or 2 and 3/4)Now we know both the slope, m = -1/8 and the y-intercept, b = 11/4.We just put these into the general form of a line and we have our equation.y = mx + by = -1/8x +11/4
The slope of a line passing through two points (x1, y1) and (x2, y2) is given by the formula: (y2 - y1) / (x2 - x1). Using the points (0, -4) and (-6, 7), the slope is: (7 - (-4)) / (-6 - 0) = 11 / -6 = -11/6.
If you mean points of: (1, 1) and (4, -1) Then the slope works out as: -2/3
Points don't have slope. In fact, they don't have anything, except location. If you want to use a couple of points to build something that has slope, one thing you could do might be to draw a line that goes through them. If you draw a line through these two points, the line has slope of negative 11/7. But the points still don't have anything except a couple of locations.
The slope of the line passing through any two points with coordinates x,y and x',y' is (y' - y)/(x' - x). In this instance, the slope is (5 - 4)/(0 - 2) = -1/2 .
Points: (-1, 7) and (-2, 3) Slope: 4 Equation: y = 4x+11
If you mean: points (-5, 11) and (5, 7) then the slope works out as -2/5
Points: (-3, 5) and (-2, -6) Slope: -11 Straight line eqution: y = -11x-28
Points: (6, 8) and (4, -3) Slope: (-3-8)/(4-6) = 11/2 or 5.5
If you mean: (2, 5) and (8, 3) then it works out as -1/3
If the points are (-7, 2) and (4, 6) then the slope of the line is 4/11
If you mean points of: (-1, 1) and (9, 4) then the slope works out as 3/10
Points: (2, 5) and (-4, 1) Slope: 2/3 Equation: 3y = 2x+11