To find the equation of a line passing through two points, we first calculate the slope using the formula (y2 - y1) / (x2 - x1). Given the points (1, 11) and (-2, 2), the slope is (2 - 11) / (-2 - 1) = -9 / -3 = 3. Next, we use the point-slope form of a linear equation, y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line. Substituting (1, 11) as the point and 3 as the slope, we get the equation y - 11 = 3(x - 1). Simplifying, we get y = 3x + 8 as the equation of the line.
Oh, dude, it's like super easy. So, you can use the point-slope form of a line, which is y - y1 = m(x - x1), where (x1, y1) is your point and m is the slope. First, find the slope using (y2 - y1) / (x2 - x1) = (2 - 11) / (-2 - 1) = -9 / -3 = 3. Then plug in the point (1, 11) and the slope into the equation: y - 11 = 3(x - 1). And there you have it, the equation of the line!
Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.
The equation of a line through (-1,7) and (-4,9) is y=-(2/3)*x+19/3
y -x + 1
The equation in slope-intercept form would be y=-2x
The general equation of a line isy = mx + cIf the gradient is 3 then m = 3 so thaty = 3x + cSince the point (4,1) lies on this line, these coordinates must satisfy the equation.So 1 = 3*4 + cie c = -11Therefore, the equation is y = 3x - 11
Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.
Points: (2, 5) and (-4, 1) Slope: 2/3 Equation: 3y = 2x+11
Points: (-1, 7) and (-2, 3) Slope: 4 Equation: y = 4x+11
The equation of a line through (-1,7) and (-4,9) is y=-(2/3)*x+19/3
A line through point (X, Y) with slope m has equation: y - Y = m(x - X) → line through (1, -1) with slope -3 has equation: y - -1 = -3(x - 1) → y + 1 = -3x + 3 → y + 3x = 2
The line goes through two numbers, so it can only be the 1-dimensional number line.
x = 1
If you mean (1, 2) and (3, 4) then its equation is y = x+1
Given points: (6, 11), (3, 10)Find: the equation of the line that passes through the given points Solution: First, wee need to find the slope m of the line, and then we can use one of the given points in the point-slope form of the equation of a line. After that you can transform it into the general form of the equation of a line. Let (x1, y1) = (3, 10), and (x2, y2) = (6, 11) slope = m = (y2 - y1)/(x2 - x1) = (11 - 10)/(6 - 3) = 1/3 (y - y1) = m(x - x1)y - 10 = (1/3)(x - 3)y - 10 = (1/3)x - 1y - 10 + 10 - (1/3)x = (1/3)x - (1/3)x + 10 - 1-(1/3)x + y = 9 which is the general form of the required line.
y -x + 1
solve the equation for y to get the slope.y=-2x-1/2substitute (3,3) into the equation/3=2(3)+band solve for b.-3=+by=2x-3 is the equation with the same slope(parallel) and goes through (3,3)
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