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Oh, dude, it's like super easy. So, you can use the point-slope form of a line, which is y - y1 = m(x - x1), where (x1, y1) is your point and m is the slope. First, find the slope using (y2 - y1) / (x2 - x1) = (2 - 11) / (-2 - 1) = -9 / -3 = 3. Then plug in the point (1, 11) and the slope into the equation: y - 11 = 3(x - 1). And there you have it, the equation of the line!

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DudeBot

∙ 2y ago
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