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What is the slope of a line perpendicular to the line 5x - 15y 20?
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What is the slope of a line perpendicular to the graph of y -8x 20?
Do you mean y = -8x+20 Then if so the perpendicular slope is positive 1/8.
What are the intercepts of the line 3x 15y 60?
x=20 y=-3
Are the lines y equals negative x minus 4 and 5x plus 5y equals 20 perpendicular explain your answer?
y=-x-4as this is in the form of y=mx+b, the slope of this line is -1.5x + 5y = 20x + y = 4y = -x + 4the slope of this line is -1.Since the slope of each of the two lines are the same (-1) they are in fact parallel to each other, not perpendicular.
What is the equation of a line that passes through 3 -4 and is perpendicular to 5x -2y equals 3 on the Cartesian plane?
Perpendicular slope: -2/5 Perpendicular equation: y--4 = -2/5(x-3) => 5y--20 = -2x-3 => 5y = -2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0
Find the slope and y - intercept of the linear equation 5x-10 equals -20?
5x - 10 = -20This equation can be restated as 5x = -10 : x = -2This is the equation of a straight line perpendicular to the x axis and passing through the point x = -2. There is no y intercept and the slope is indeterminate.
What is the slope of a line perpendicular to the graph of y -8x 20?
Do you mean y = -8x+20 Then if so the perpendicular slope is positive 1/8.
What are the intercepts of the line 3x 15y 60?
x=20 y=-3
How do you solve 3xy-4x plus 15y-20?
3xy-4x + 15y-20 Sol: As there are no number are same. So -4x-3xy +15y-20 -------------------- -4x-3xy+15y-20
Are the lines y equals negative x minus 4 and 5x plus 5y equals 20 perpendicular explain your answer?
y=-x-4as this is in the form of y=mx+b, the slope of this line is -1.5x + 5y = 20x + y = 4y = -x + 4the slope of this line is -1.Since the slope of each of the two lines are the same (-1) they are in fact parallel to each other, not perpendicular.
What is the equation of the line that passes through the point of 3 -4 and is perpendicular to the line 5x -2y equals 3?
Known equation: 5x -2y=3 => y=5/2x -1.5 Slope of equation: 5/2 Perpendicular slope: -2/5 Perpendicular equation: y--4=-2/5(x-3) => 5y--20=-2x+6 => 5y=-2x-14 Therefore the perpendicular in its general form is: 2x+5y+14 = 0
What is the equation of a line that passes through 3 -4 and is perpendicular to 5x -2y equals 3 on the Cartesian plane?
Perpendicular slope: -2/5 Perpendicular equation: y--4 = -2/5(x-3) => 5y--20 = -2x-3 => 5y = -2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0
What is the slope of the line that passes through the points 14 5 and 20 4?
Points: (14, 5) and (20, 4) Slope: -1/6
Find the slope parallel to x y 20?
Parallel lines have the same slope. So if you have y=x+20 for example, the slope is 1 and any parallel line has slope 1 also. I think your equation is x=y+20 but since the+ and - don't show up i am not sure If it is we can rewrite it as -y=-x+20 or y=x-20 and slope is still 1 so any parallel line has slope 1.
What is the slope of this equation y equals 20-3X?
23
What is the perpendicular distance from the point 2 4 to the straight line y equals 2x plus 10?
It is 2√5 ≈ 4.47 units.To solve this:Find the equation of the line perpendicular to y = 2x + 10 that passes through the point (2, 4);Find the point where this line meets y = 2x + 10Find the distance from this point to (2, 4) using PythagorasThe slope of the perpendicular line (m') to a line with slope m is such that mm' = -1, ie m' = -1/mFor y = 2x + 10, the perpendicular line has slope -1/2, and so the line that passes through (2, 4) with this slope is given by:y - 4 = -½(x - 2)→ 2y - 8 = -x + 2→ 2y + x = 10To find where this meets the line y = 2x + 10, substitute for y in the equation of the perpendicular line and solve for x:y = 2x + 102y + x = 10→ 2(2x + 10) + x = 10→ 4x + 20 + x = 10→ 5x = -10→ x = -2Now use one of the equations to solve for y:y = 2x + 10→ y = 2(-2) + 10→ y = -4 + 10 = 6This the perpendicular line from (2, 4) meets the line y = 2x + 10 at the point (-2, 6)The distance between these two points is given by:distance = √((-2 - 2)² + (6 - 4)²) = √(16 + 4) = √20 = 2√5 ≈ 4.47 units
What is a slope of the line that passes through-20,-4 and -12,-10?
I believe the slope would be: -4 / 3
Find the slope and y - intercept of the linear equation 5x-10 equals -20?
5x - 10 = -20This equation can be restated as 5x = -10 : x = -2This is the equation of a straight line perpendicular to the x axis and passing through the point x = -2. There is no y intercept and the slope is indeterminate.
