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If you mean: y = 4x+5 then the perpendicular slope is -1/4
Perpendicular slope: -1/4 Perpendicular equation: y-0 = -1/4(x-3) => y = -0.25x+3
Take the negative reciprocal of the lines slope you want it to be perpendicular to. For example y = 3x +2; perpendicular line slope is -1/3.
The slope is -0.2
First, convert the equation to Slope-Intercept Form (y = mx + b) m = slope b = y-intercept 3x - 4y = 8 Subtract 3x from both sides of the equation. -4y = -3x + 8 Divide the entire equation by -4. y = 3/4x -2 Now that we know that the slope is 3/4, we can convert it to its perpendicular slope. The perpendicular slope is the opposite reciprocal of the original slope. In order to find it, we flip the fraction and change the sign. Original Slope: 3/4 Perpendicular Slope: -4/3
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The equation has been distorted in the question (as usual on this site). The general idea is to solve the equation for "y"; read off the slope from the resulting equation; then divide minus 1 by this slope to get the slope of the perpendicular line.
If you mean: y = 5x-2 then the perpendicular slope is -1/5
If you mean: y = 4x+5 then the perpendicular slope is -1/4
Perpendicular slope: -1/4 Perpendicular equation: y-0 = -1/4(x-3) => y = -0.25x+3
7/9
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Take the negative reciprocal of the lines slope you want it to be perpendicular to. For example y = 3x +2; perpendicular line slope is -1/3.
Get the slope of the given line, by putting it into slope-intercept form. Then you can divide minus one by this slope, to get the slope of any perpendicular line.
The slope is -0.2
Points: (3,-4) and (-1, -2) Midpoint: (1,-3) Slope: -1/2 Perpendicular slope: 2 Perpendicular bisector equation in slope intercept form: y = 2x-5
If you mean y = 2x+5 then the perpendicular slope is -1/2