If you mean: y = 4x+5 then the perpendicular slope is -1/4
To find the slope of the line perpendicular to the given equation, we first need to determine the slope of the original line. The equation (-4x + 3y = -32) can be rearranged into slope-intercept form (y = mx + b). Solving for (y), we get (3y = 4x - 32) or (y = \frac{4}{3}x - \frac{32}{3}), which has a slope of (\frac{4}{3}). The slope of a line perpendicular to this would be the negative reciprocal, which is (-\frac{3}{4}).
-- The slope of the graph of [ 4x + y = 2 ] is -4.-- The slopes of perpendicular lines are negative reciprocals.-- The slope of any line perpendicular to [ 4x + y = 2 ] is 1/4 .
Points: (-2, 3) and (1, -1) Midpoint: (-0.5, 1) Slope: -4/3 Perpendicular slope: 4/3 Equation: 3y = -4x+1 Perpendicular bisector equation: 4y = 3x+5.5
Equation: 3x+4y = 0 => y = -3/4x Perpendicular slope: 4/3 Perpendicular equation: 4x-3y-13 = 0 Equations intersect at: (2.08, -1.56) Distance from (7, 5) to (2.08, -1.56) = 8.2 units using the distance formula
To find the equation of the line perpendicular to (y - 4x + 2 = 0), we first determine the slope of the given line, which is 4. The slope of the line perpendicular to it will be the negative reciprocal, (-\frac{1}{4}). Using the point (4, 4) and the point-slope form of the equation (y - y_1 = m(x - x_1)), we have: [ y - 4 = -\frac{1}{4}(x - 4). ] This simplifies to (y = -\frac{1}{4}x + 5).
The equation has been distorted in the question (as usual on this site). The general idea is to solve the equation for "y"; read off the slope from the resulting equation; then divide minus 1 by this slope to get the slope of the perpendicular line.
4x+5y = 7 5y = -4x+7 y = -4/5x+7/5 in slope intercept form So the slope of the perpendicular line is plus 5/4
To find the slope of the line perpendicular to the given equation, we first need to determine the slope of the original line. The equation (-4x + 3y = -32) can be rearranged into slope-intercept form (y = mx + b). Solving for (y), we get (3y = 4x - 32) or (y = \frac{4}{3}x - \frac{32}{3}), which has a slope of (\frac{4}{3}). The slope of a line perpendicular to this would be the negative reciprocal, which is (-\frac{3}{4}).
If you mean: y = -4x+3 then the perpendicular slope is 1/4
4y= -3x + 12 y = -3/4x + 3 The perpendicular slope is 4/3
Perpendicular equation: 4x +3y -5 = 0 Perpendicular slope: -4/3 Slope of line: 3/4 Point of line: (-2, -3) Equation of line: y - -3=3/4(x - -2) => 4y - -12=3x - -6 => 4y = 3x -6 Therefore the equation of the line is: 4y = 3x -6 or 3x -4y -6 = 0
If you mean point (-1, 4) and equation of 4x-3y = -9 then y = 4/3x+3 Slope of equation: 4/3 Perpendicular slope: -3/4 Perpendicular equation: y-4 = -3/4(x--1) => 4y = -3x+13
what is the slope of the line that has the equation 4x+2y=12?
-- The slope of the graph of [ 4x + y = 2 ] is -4.-- The slopes of perpendicular lines are negative reciprocals.-- The slope of any line perpendicular to [ 4x + y = 2 ] is 1/4 .
4x+2y = 6 2y = -4x+6 y = -2x+3 Perpendicular slope is 1/2
If you mean: y = 4x+2 then the line perpendicular to it will have a slope of -1/4
Points: (-2, 3) and (1, -1) Midpoint: (-0.5, 1) Slope: -4/3 Perpendicular slope: 4/3 Equation: 3y = -4x+1 Perpendicular bisector equation: 4y = 3x+5.5