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What is the equation of the line passing through -2 -3 that is at right angles to the equation 4x plus 3y -5 equals 0 on the Cartesian plane?
The equation will be perpendicular to the given equation and have a slope of 3/4:- Perpendicular equation: y--3 = 3/4(x--2) => 4y--12 = 3x--6 => 4y = 3x-6 Perpendicular equation in its general form: 3x-4y-6 = 0
What Line t is the perpendicular bisector of FG. If line t intersects FG at point H statements must be true Check all that apply.?
The answer letters always rearrange so here are the answers point H is the midpoint of FG line t intersects FG at a right angle Line T is perpendicular to FG
What is the straight line equation passing through points 4 and 0 when it is perpendicular to x plus 7y plus 4 equals 0?
x+7y+4 = 0 => y = -1/7x-4/7 The slope of the second equation is the reciprocal of the first equation with the minus sign changing to a plus sign. y = mx+c where m is the slope and c is the intercept on the y axis So: 7*4+c = 0 28+c = 0 c = -28 Therefore the perpendicular equation is: y = 7x-28 which can be expressed in the form of 7x-y-28 = 0
What is the slope of the line perpendicular to the line passing through the points 5-1 and 2-5?
Points: (5, -1) and (2, -5) Slope: 4/3 Perpendicular slope: -3/4
What is a term used to describe the relationship between two variables who's graph is a straight line passing through the point 00?
It is a straight line equation with no x or y intercepts on the Cartesian plane
What is the perpendicular bisector equation passing through the line segment of 7 7 and 3 5 giving brief details?
Points: (7, 7) and (3, 5) Midpoint: (5, 6) Slope: 1/2 Perpendicular slope: -2 Use: y-6 = -2(x-5) Perpendicular bisector equation: y = -2x+16 or as 2x+y-16 = 0
How do you form an equation for the perpendicular bisector of the line segment joining -2 5 to -8 -3?
First find the midpoint of (-2, 5) and (-8, -3) which is (-5, 1) Then find the slope of (-2, 5) and (-8, -3) which is 4/3 Slope of the perpendicular bisector is the negative reciprocal of 4/3 which is -3/4 Now form an equation of the straight line with a slope of -3/4 passing through the point (-5, 1) using the formula y-y1 = m(x-x1) The equation works out as: 3x+4y+11 = 0
What in its general form is the perpendicular bisector equation passing through the line segment of h k and 3h -5k showing key stages of your work?
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What is the perpendicular bisector equation of the line segment whose end points are at 7 3 and -6 1?
To solve this, four steps are needed:Find the midpoint of the line segment (X, Y) which is a point on the perpendicular bisectorFind the slope m for the line segment: m = change_in_y/change_in_xFind the slope m' of the perpendicular line; the slopes of the lines are related by mm' = -1 → m' = -1/mFind the equation of the perpendicular bisector using the slope-point equation for a line passing through point (X, Y) with slope m': y - Y = m'(x - X)Have a go before reading the solution below.--------------------------------------------------------------------The midpoint of (7, 3) and (-6, 1) is at ((7 + -6)/2, (3 + 1)/2) = (1/2, 2)The slope of the line segment is: m = change_in_y/change_in_x = (1 - 3)/(-6 - 7) = -2/-13 = 2/13The slope of the perpendicular bisector is m' = -1/m = -1/(2/13) = -13/2The equation of the perpendicular bisector passing through point (X, Y) = (1/2, 2) with slope m' = -13/2 is given by:y - Y = m'(x - Y)→ y - 2 = -13/2(x - 1/2)→ 4y - 8 = -26x + 13→ 4y + 26x = 21
What is the equation of the line passing through 3 -4 and it is perpendicular to the line 5x -2y equals 3?
Known equation: 5x -2y = 3 or y = 5/2x -3/2 Slope of equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y --4 = -2/5(x -3) => 5y = -2x -14 Perpendicular equation in its general form: 2x+5y+14 = 0
What is the equation of the line passing through -2 -3 that is at right angles to the equation 4x plus 3y -5 equals 0 on the Cartesian plane?
The equation will be perpendicular to the given equation and have a slope of 3/4:- Perpendicular equation: y--3 = 3/4(x--2) => 4y--12 = 3x--6 => 4y = 3x-6 Perpendicular equation in its general form: 3x-4y-6 = 0
What equation represents a line perpendicular to y equals x and passing through the points 0 0?
y=-x
What is the equation passing through the point 3 -4 which is perpendicular to the line 5x -2y equals 3?
Known equation: 5x-2y = 3 or y = 5/2x -3/2 Slope of known equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y- -4 = -2/5(x-3) => 5y =-2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0
How to find the perpendicular distance between two points?
To find the perpendicular distance between two points, you can use the distance formula and the concept of perpendicular lines. First, calculate the distance between the two points using the distance formula. Then, find the slope of the line passing through the two points. The perpendicular distance is the length of the line segment that connects the two points and forms a right angle with the line passing through them.
What is a line perpendicular to a line segmentt and passing through its midpoint?
There is no name for it except "A line perpendicular to a line segment and passing through its midpoint".
What is the equation that represents the line perpendicular to y equals -3x plus 4 and passing through the point -1 1?
y = 1/3x+4/3
What is the equation of the line passing through the point -2 -3 and is perpendicular to the line 4x plus 3y -5 equals 0?
Perpendicular equation: 4x +3y -5 = 0 Perpendicular slope: -4/3 Slope of line: 3/4 Point of line: (-2, -3) Equation of line: y - -3=3/4(x - -2) => 4y - -12=3x - -6 => 4y = 3x -6 Therefore the equation of the line is: 4y = 3x -6 or 3x -4y -6 = 0
